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3 years ago

Please answer will mark as brainliest

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

Answer:

Nine below zero
Nine less than zero
The opposite of nine

I hope this helps!

blondinia [14]3 years ago

6 0

Answer:

nine below zero

nine less than zero

the opposite of 9

Step-by-step explanation:

(brainliest plz)

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For the complex number 10+12i identify the real part and the imaginary part

SpyIntel [72]

Complex number = a +bi

a is a real part, bi - an imaginary part

So, in <span>10+12i
10 is a real part, 12i is an imaginary part.</span>

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3 years ago

Write the product using exponents.

nalin [4]

6.4^4 (b^3) or as shown in photo

3 0

2 years ago

I need help proving this ASAP

Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

$\tan(x + \frac{3\pi}{2} ) = - \cot \: x$

One way is to use the basic double angle formula:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) \cos( \frac{3\pi}{2} ) + \cos(x) \sin( \frac{3\pi}{2}) }{\cos(x) \cos( \frac{3\pi}{2} ) - \sin(x) \sin( \frac{3\pi}{2}) }$

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) ( 0) + \cos(x) ( - 1) }{\cos(x) (0) - \sin(x) ( - 1) }$

We simplify further to get:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ 0 - \cos(x) }{0 + \sin(x) }$

We simplify again to get;

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{- \cos(x) }{ \sin(x) }$

This finally gives:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = - \cot(x)$

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Answer: n=0.4 or 2/5

Step-by-step explanation:

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3 years ago

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Alex17521 [72]

Answer:

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3 years ago

Read 2 more answers