Your answer should be 168.40
The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
b = 33m is the answer
Step-by-step explanation:
a = 44m
b = ?
c = 55m
According to the Pythagoras theorem,
a² + b² = c²
44² + b² = 55²
1936 + b² = 3025
b² = 3025 - 1936
b² = 1089
b = 33m
∴ b = 33m is the length of the missing leg.
Answer:
x^2 +x +1
Step-by-step explanation:
See below for the tableau. The quotient is x^2 +x +1.
___
The remainder is 2.
