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Oksi-84 [34.3K]
3 years ago
15

Stallone's sub shop purchased a delivery van for $24,000. Suppose that MACRS allows delivery vans to be depreciated fully in 6 y

ear according to six fixed percents. 20% the first year, 32% the second year, 19.2% the third year, 11.52% the fourth and fifth years, and 5.76% the sixth year. What is the annual depreciation for the second year?
Mathematics
2 answers:
Mumz [18]3 years ago
5 0

Answer:

The annual depreciation for the second year is $7,680.

Step-by-step explanation:

Stallone's sub shop purchased a delivery van for $24,000.

20% the first year, 32% the second year, 19.2% the third year, 11.52% the fourth and fifth years, and 5.76% the sixth year.

The annual depreciation is : The cost of the van * depreciation rate(of desired year)

The depreciation rate is 32% in the second year, so:

For, 2nd year the depreciation will be = 0.32\times24000=7680 dollars.

Therefore, the annual depreciation for the second year is $7,680.

PSYCHO15rus [73]3 years ago
4 0
Hi there

The annual depreciation rate for the second year is 32.%
So the annual depreciation is
24,000×0.32=7,680

Hope it helps
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Suppose that a box contains 7 cameras and that 5 of them are defective. A sample of 2 cameras is selected at random without repl
irinina [24]

Answer:

E(x) = 1.43 (Approx)

Step-by-step explanation:

Given:

Total number of camera = 7

Defective camera = 5

Sample selected = 2

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when x = 0

P(x=0) = 2/7 × 1/6 = 2/42

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P(x=2) = 5/7 × 4/6 = 20/42

So,

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3 years ago
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Lesechka [4]

The correct question is;

You spin the spinner, flip a coin, then spin the spinner again. Find the probability of the compound event. Write your answer as a fraction or percent. If necessary round your answer to the nearest hundredth. Find the probability of spinning an odd number, flipping heads, then spinning another odd number? Write your answer as a fraction in simplest form.

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If the spinner has an even number of spaces, the probability of spinning an odd number, flipping heads, then spinning a yellow is = 1/8

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The answer will depend on whether the spinner has an odd or even number of spaces.

Now, if we suppose that the spinner has an even amount of numbers on it, there will be an equal number of odd and even numbers.

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