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Oksi-84 [34.3K]
3 years ago
15

Stallone's sub shop purchased a delivery van for $24,000. Suppose that MACRS allows delivery vans to be depreciated fully in 6 y

ear according to six fixed percents. 20% the first year, 32% the second year, 19.2% the third year, 11.52% the fourth and fifth years, and 5.76% the sixth year. What is the annual depreciation for the second year?
Mathematics
2 answers:
Mumz [18]3 years ago
5 0

Answer:

The annual depreciation for the second year is $7,680.

Step-by-step explanation:

Stallone's sub shop purchased a delivery van for $24,000.

20% the first year, 32% the second year, 19.2% the third year, 11.52% the fourth and fifth years, and 5.76% the sixth year.

The annual depreciation is : The cost of the van * depreciation rate(of desired year)

The depreciation rate is 32% in the second year, so:

For, 2nd year the depreciation will be = 0.32\times24000=7680 dollars.

Therefore, the annual depreciation for the second year is $7,680.

PSYCHO15rus [73]3 years ago
4 0
Hi there

The annual depreciation rate for the second year is 32.%
So the annual depreciation is
24,000×0.32=7,680

Hope it helps
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3 years ago
NEED HELP
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The solutions to the systems of equations are:

1. (2, 3) (see attachment below). [one solution]

2. no solution

3. (3, 13) [one solution]

<h3>Solution to a System of Equations?</h3>

The solution to a system of equations is the x-value and y-value that will make both equations true. It can be found either using a graph, by elimination method, or substitution method as explained below.

1. Using graph to solve y = 2x - 1 and y = 4x - 5:

The solution is the point where both lines intersect which is: (2, 3) (see attachment below). [one solution]

2. Solving using substitution method:

x = -5y + 4 ---> eqn. 1

3x + 15y = -1 ---> eqn. 2

Substitute x = -5y + 4 into eqn. 2

3(-5y + 4) + 15y = -1

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-15y + 15y = -1 - 12

0 = -13 (this shows that there is no solution)

3. Using elimination method:

14x = 2y + 16 ---> eqn. 1

5x = y + 2 ---> eqn. 2

1(14x = 2y + 16)

2(5x = y + 2)

14x = 2y + 16 ----> eqn. 3

10x = 2y + 4 -----> eqn. 4

Subtract

4x = 12

x = 12/4

x = 3

Substitute x = 3 into eqn. 2

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15 = y + 2

15 - 2 = y

13 = y

y = 13

The solution is: (3, 13).

Learn more about the solution of a system of equations on:

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Step-by-step explanation:

a.

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Let x = number of offers made

X is said to be discrete if x can take values that are restricted to a defined or limited values

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Looking at the brief description above, we can conclude that x is discrete

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Answer:

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