Given the equation, S = D/T:
To make the D the subject of the equation, we can start by multiplying both sides by T to isolate D:
(T) S = D/T (T)
TS = D
Therefore, the final answer is D = TS
⅔ and 8/12 form a proportion.
Parameterize
by

with
and
. Take a normal vector to
,

which has norm

Then the integral of
over
is


Ignore the scribbles
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