I think 140 is the answer
Answer:
y=51, z and x= 129
Step-by-step explanation:
its complicated, but try to think of it as 51 and x/z are complementary angles, meaining they are on the same line, which means they equal 180, which makes this easier to solve meaning all you have to do is subtract 180-51=129.
Let
V-------------> total <span>vegetables in Priya's garden
T------------> total tomatoes </span>in Priya's garden
we know that
T=(2/5)V
Part A) <span>HOW many tomatoes are there I'd Priya's garden has.
1) </span><span>20 Vegetables?
</span>T=(2/5)*20----------> 20*2/5---------> 8 tomatoes
<span>the answer Part A1) is 8 tomatoes
</span>
2) x Vegetables?
T=(2/5)*x----------> x*2/5---------> (2/5)*x ----------> 0.40*x tomatoes
the answer Part A2) is (0.40)*x tomatoes
Part B) <span>Priya's garden has 6 tomatoes. How many total vegetables are there?
</span>T=(2/5)V-----------> V=5T/2--------> V=(5*6)/2--------> V=15 vegetables
<span>
the answer part B) is </span>15 vegetables<span>
</span>
Answer:
=21k-18
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given (64 y Superscript 100 Baseline) Superscript one-half.
Let us write it into an equation.
Apply radical rule: ![\sqrt[n]{a}=a^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
and 
![\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cleft%2864%20y%5E%7B100%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%26%3D%5Csqrt%5B2%5D%7B64%20y%5E%7B100%7D%7D%20%5C%5C%26%3D%5Csqrt%5B2%5D%7B8%5E%7B2%7D%20y%5E%7B50%7D%20y%5E%7B50%7D%7D%20%5C%5C%26%3D%5Csqrt%5B2%5D%7B8%5E%7B2%7D%5Cleft%28y%5E%7B50%7D%5Cright%29%5E%7B2%7D%7D%20%5C%5C%26%3D8%20y%5E%7B50%7D%5Cend%7Baligned%7D)
Hence, is equivalent to (64 y Superscript 100 Baseline) Superscript one-half.
