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3 years ago

I NEED HELP PLEASEEEEEEEEEEE I CANT DO IT PLEASE JELP ASAP

Mathematics

2 answers:

Ksivusya [100]3 years ago

6 0

Answer:

D: its 18

Step-by-step explanation:

I yeeted it into a calculator

ahrayia [7]3 years ago

3 0

Answer: D
[3 divided by 1/6] 6
18 divided by 1
18

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Sarah made $130 for 9 hours of work. At the same rate, how many hours will she have to work to make $165?

meriva

I believe she will have to work 12 hours!

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In the 1939 movie The Wizard of Oz, upon being presented with a Th.D. (Doctor of Thinkology), the Scarecrow proudly exclaims, "T

Brilliant_brown [7]

Answer:

The Scarecrow got it wrong.

Step-by-step explanation:

1. The Pythagoras theorem does not apply to every isosceles triangle. It only applies to a triangle that has one of its sides as a right angle i.e. 90 degrees.

2. The Pythagoras theorem deals with squares of sides not square roots of sides.

3. Pythagoras theorem does not state that the square of any side is equal to the sum of the remaining two. Instead, it states that the square of the hypotenuse of a right angled triangle is equal to the sum of the square of the remaining two sides.

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3 years ago

May someone please help me with this question

Cloud [144]

Answer:

2+i or 2-i (D)

Step-by-step explanation:

First you use the quadratic formula. X= (-b +/- $\sqrt{b^{2}-4ac }$ )/2a

a=1

b=-4

c=5

X= (4 +/- $\sqrt{16-20}$ )/2

X=(4 +/- $\sqrt{-4}$ )/2

The square root of -4 is 2i. i=√-1. Therefore 2i= 2√-1 .If you simplify that, it becomes √-4i.

X= (4+/- 2i)/2

X= 2+/-i

X= 2+i or 2-i

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3 years ago

Write an equation for a circle with a diameter that has endpoints at (–3, –2) and (7, –6). Round to the nearest tenth if necessa

jarptica [38.1K]

The standard form for the equation of a circle is :

(x−h)^2+(y−k)^2=r2 ----------- EQ(1)

where handk are the x and y coordinates of the center of the circle and r is the radius.

The center of the circle is the midpoint of the diameter.

So the midpoint of the diameter with endpoints at (−3,-2)and(7,-6) is :

((−3+7)/2,(-2+(-6))/2)=(2,-4)

So the point (2,-4) is the center of the circle.

Now, use the distance formula to find the radius of the circle:

r^2=(−3−(2))^2+(-2-(-4))^2=25+4=29

⇒r=√29

Subtituting h=2, k=-4 and r=√29 into EQ(1) gives :

(x-2)^2+(y+4)^2=29

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3 years ago

5x+25=75 pls help appreciated

Dafna11 [192]

Answer:

x=10

Step-by-step explanation:

I guess solve for x

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