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3 years ago

Can I have help with 9 it’s seems easy but I need help

Mathematics

1 answer:

victus00 [196]3 years ago

3 0

A number coming out of an absolute value is ALWAYS positive.
A. 45
B. 8
C. -22
D. -4

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PLS HELP ILL GIVE BRAINLIEST WHOEVER ANSWERS PLS :(

erica [24]

Answer:

stem: 5

leaf: 0, 6

stem: 6

leaf: 0, 2, 5, 6

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i hope this helps <3

Step-by-step explanation:

4 0

3 years ago

A 20-year loan of 1000 is repaid with payments at the end of each year. Each of the first ten payments equals 150% of the amount

Alja [10]

Answer:

$x = 97$

Step-by-step explanation:

Given

$t = 20$ --- time (years)

$A =1000$ --- amount

$r = 10\%$ --- rate of interest

Required

The last 10 payments (x)

First, calculate the end of year 1 payment

$y_1(end) = 10\% * 1000 * 150\%$

$y_1(end) = 150$

Amount at end of year 1

$A_1=A - y_1(end) - r * A$

$A_1=1000 - (150 - 10\% * 1000)$

$A_1 =1000 - (150- 100)$

$A_1 =950$

Rewrite as:

$A_1 = 0.95 * 1000^1$

Next, calculate the end of year 1 payment

$y_2(end) = 10\% * 950 * 150\%$

$y_2(end) = 142.5$

Amount at end of year 2

$A_2=A_1 - (y_2(end) - r * A_1)$

$A_2=950 - (142.5 - 10\%*950)$

$A_2 = 902.5$

Rewrite as:

$A_2 = 0.95 * 1000^2$

We have been able to create a pattern:

$A_1 = 1000 * 0.95^1 = 950$

$A_2 = 1000 * 0.95^2 = 902.5$

So, the payment till the end of the 10th year is:

$A_{10} = 1000*0.95^{10}$

$A_{10} = 598.74$

To calculate X (the last 10 payments), we make use of the following geometric series:

$Amount = \sum\limits^{9}_{n=0} x * (1 + r)^n$

$Amount = \sum\limits^{9}_{n=0} x * (1 + 10\%)^n$

$Amount = \sum\limits^{9}_{n=0} x * (1 + 0.10)^n$

$Amount = \sum\limits^{9}_{n=0} x * (1.10)^n$

The amount to be paid is:

$Amount = A_{10}*(1 + r)^{10}$ --- i.e. amount at the end of the 10th year * rate of 10 years

$Amount = 1000 * 0.95^{10} * (1+r)^{10}$

So, we have:

$Amount = \sum\limits^{9}_{n=0} x * (1.10)^n$

$\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+r)^{10}$

$\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+10\%)^{10}$

$\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+0.10)^{10}$

$\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1.10)^{10}$

The geometric sum can be rewritten using the following formula:

$S_n = \sum\limits^{9}_{n=0} x * (1.10)^n$

$S_n =\frac{a(r^n - 1)}{r -1}$

In this case:

$a = x$

$r = 1.10$

$n =10$

So, we have:

$\frac{x(r^{10} - 1)}{r -1} = \sum\limits^{9}_{n=0} x * (1.10)^n$

$\frac{x((1.10)^{10} - 1)}{1.10 -1} = \sum\limits^{9}_{n=0} x * (1.10)^n$

$\frac{x((1.10)^{10} - 1)}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n$

$x * \frac{1.10^{10} - 1}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n$

So, the equation becomes:

$x * \frac{1.10^{10} - 1}{0.10} = 1000 * 0.95^{10} * (1.10)^{10}$

Solve for x

$x = \frac{1000 * 0.95^{10} * 1.10^{10} * 0.10}{1.10^{10} - 1}$

$x = 97.44$

Approximate

$x = 97$

4 0

4 years ago

The weights of the chocolate in Hershey Kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.10

dusya [7]

The distribution is not a standard normal distribution.

We know that the variable (X) usually obeys and follows a standard normal distribution provided that the summation of (X) is zero and the variance of the random variable V(X) = 1.

Mathematically:

E(X) = 0 and V(X) = 1

Given that;

the mean which follows a normal distribution (X) = 4.5338 g, and
the standard deviation SD(X) = 0.1039 g

As such, the distribution is not a standard normal distribution.

Therefore, we can conclude that the distribution is not a standard normal distribution.

Learn more about standard normal distribution here:

brainly.com/question/11876263?referrer=searchResults

7 0

3 years ago

Vertex of y=-x^2+2x+1

White raven [17]

Answer:

Step-by-step explanation:

1232 7438494

8 0

3 years ago

Read 2 more answers

I don't know how to solve this helpp

Aleksandr-060686 [28]

neverminding the jumbled lingo, is simply asking for the equation of the tangent line at that point, it says all tangents, well, there's only one passing there.

we can simply get the derivative of f(x) and take it from there.

$f(x)=4-x^2+2x\implies \left. \cfrac{df}{dx}=-2x+2 \right|_{x=\frac{3}{2}}\implies -2(\frac{3}{2})+2\implies -1$

since now we know the slope when x = 3/2, then we can just plug that into its point-slope intercept form, along with the coordinates.

$(\stackrel{x_1}{\frac{3}{2}}~,~\stackrel{y_1}{7})~\hfill \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{-1}(x-\stackrel{x_1}{\frac{3}{2}}) \\\\\\ y-7=-x+\cfrac{3}{2}\implies y=-x+\cfrac{17}{2}$

6 0

3 years ago