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3 years ago

Volume of triangular prism

Mathematics

2 answers:

galina1969 [7]3 years ago

5 0

Answer:

216

Step-by-step explanation:

9 * 6 = 54

54 * 8 = 432

432/2 = 216 is the answer

sweet-ann [11.9K]3 years ago

4 0

The volume of a triangular prism is the area of the base multiplied by the height. This can be represented as volume = base × height

Let's first identify our values:

9 m = height of the prism

6 m = base of the triangle

8 m = height of the triangle

First, we need to calculate the area of the triangle. To calculate the area of a triangle, the formula is base × height ÷ 2.

The base of the triangle is 6 and the height of the triangle is 8 so 6 multiplied by 8 will give us a product of 48. Next, we need to divide 48 by 2 and we will get a quotient of 24.

Finally, we need to multiply the area of the triangle by the height of the prism.

24 × 9 = 216

Therefore, the volume of the triangular prism is 216 $m^{3}$

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zaharov [31]

Negative times negative = positive.

=0.63−(−9.85)
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5 0

3 years ago

Read 2 more answers

A closed cylindrical vessel contains a fluid at a 5MPa pressure. The cylinder, which has an outside diameter of 2500mm and a wal

Julli [10]

Answer:

1) Increase in the diameter equals 3.5 mm

2) Increase in the length equals $0.0003724L_{i}$ where $L_{i}$ is the initial length of the vessel.

Step-by-step explanation:

The diametric strain in the vessel is given by

$\epsilon_{D} =\epsilon_{diam}-\nu \epsilon _{axial}$

We have

$\epsilon _{diam}=\frac{\sigma _{hoop}}{E}\\\\\sigma _{hoop}=\frac{\Delta P\times D}{2t}\\\\\therefore \epsilon _{diam}=\frac{\Delta P\times D}{2t\times E}$

Applying values we get

$\therefore \epsilon _{diam}=\frac{5\times 10^{6}\times 2.5}{2\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{5}{3088}$

Similarly axial strain is given by

$\epsilon _{diam}=\frac{\sigma _{axial}}{E}$

$\sigma _{axial}=\frac{\Delta P\times D}{4t}\\\\\therefore \epsilon _{axial}=\frac{\Delta P\times D}{4t\times E}$

Applying values we get

$\therefore \epsilon _{axial}=\frac{5\times 10^{6}\times 2.5}{4\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{2.5}{3088}$