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Anika [276]
3 years ago
6

If the area of a circle measures 25π cm2, what is the circumference of the circle in terms of π? A) 5π cm B) 10π cm C) 50π cm D)

100π cm
Mathematics
2 answers:
Bad White [126]3 years ago
8 0

the answer to the question is a.) 5rr cm because 5rr is right on brainly i've had it


Sliva [168]3 years ago
6 0
<h2><em><u>Answer:</u></em></h2><h2><em><u>The correct answer is B) 10 pi cm</u></em></h2><h2><em><u>Step-by-step explanation:</u></em></h2><h2><em><u>10π cm </u></em></h2><h2><em><u /></em></h2><h2><em><u>A = πr2 </u></em></h2><h2><em><u>25π = πr2 </u></em></h2><h2><em><u>25 = r2 </u></em></h2><h2><em><u>5 = r </u></em></h2><h2><em><u /></em></h2><h2><em><u>C = 2πr </u></em></h2><h2><em><u>C = 2π(5) </u></em></h2><h2><em><u>C = 10π</u></em></h2>
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2. Ans: Option (D) -3y^5

Explanation:
Given: 6y^5 - 9y^5
Take the common term(s) out:
=> y^5(6-9)

Hence: => -3y^5 (Option D)

3. Ans: Option (B) 9x^2 - 12x + 6<span> quadratic trinomial 

Explanation:
</span>Given: 6 - 12x + 13x^2 - 4x^2

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> 
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=> 9x^2 - 12x + 6 (Option B)

4. Ans: Option (C) 7.3x^2 + 0.8x + 1.3

Explanation:
In order to find the total number of C<span>ommon and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

</span>Common guppies: 3.1x^2 +6.0x + 0.3<span>
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Total number:          7.3x^2 +0.8x + 1.3
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Hence the ans is Option(C) 7.3x^2 + 0.8x + 1.3

5. Ans: Option (D) 2x^2(133 - 18 \pi )

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = 266x^2

Now the area of the circular fountain:
Area of the Circular Fountain = \pi r^2
Since, r=6x
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Area of the Circular Fountain = \pi (6x)^2 = 36 \pi x^2

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = 266x^2 - 36 \pi x^2
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Explanation:
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Now the final Area of the lot would be:
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4 0
3 years ago
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