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choli [55]
3 years ago
6

Help 0.06 is 10 times as much as

Mathematics
2 answers:
DedPeter [7]3 years ago
6 0
0.06 is 10 times as much as:

= 0.06/10
= 0.006.

That's it.
Ipatiy [6.2K]3 years ago
3 0

Answer:

0.06 is 10 times as much as 0.006

Step-by-step explanation:

let the number be x

as per the condition 0.06 is 10 times as much as x.

Solve for x:

10 times as much as x represents as 10 \times x

Then;

0.06 = 10 \times x                 ......[1]

Division property of equality states that you divide the same number to both sides of an equation.

divide by 10 to both sides in equation [1];

\frac{0.06}{10} = \frac{10x}{x}

Simplify:

x = 0.006

Therefore, 0.06 is 10 times as much as 0.006


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F=(9/5) C +32, C=15 Can you show me what a graph looks like?
CaHeK987 [17]

Answer:

Step-by-step explanation:

F=(9/5) C +32 has the form of the equation of a straight line:  y = mx + b, where m is the slope and b is the y-intercept.  By comparing these two equations we see that the slope, m, is (9/5) and the y-intercept is 32 (or (0, 32)).

To graph this, first locate the y-intercept (0, 32); put a dark dot there.  Since the slope is 32, or 32/1, move your pencil point 1 unit to the right, from (0, 32) to (1, 32), and then from (1, 32) move y our pencil point 32 units upward.  Plot another dark dot there and then draw a straight line through these two points.

We can evaluate the given function F=(9/5) C +32 at C = 15 by replacing C in the formula with 15:  F = (9/5)(15) + 32, or F = 59.

8 0
3 years ago
Helpp <br> find the slope <br> 1. -1/2<br> 2. -2<br> 3. 1/2<br> 4. 2
makkiz [27]

Answer:

1. -1/2 is the answer

Step-by-step explanation:

7 0
3 years ago
Y = 5x - 10<br> Can you solve for x
tensa zangetsu [6.8K]

Answer:

x = \frac{1}{5}y + 2     or       x = \frac{y+10}{5}     (Not sure which one is preferred in your case)

Step-by-step explanation:

<u>Key skills needed: Evaluating expressions</u>

1) We are given: y = 5x-10

2) To solve for the x variable, we want to leave the term with "x" by itself.

This means we add 10 to both sides

--> y + 10 = 5x (Since -10 and +10 cancel out to make 0 or nothing)

3) Then we divide by 5 on both sides to get "x" completely by itself.

-----> \frac{y+10}{5} = x

4) You can keep it as is so --> x = \frac{y + 10}{5}

or you can divide "y" by 5 and "10" by 5 and get --> x = \frac{1}{5} y + 2

(I am not sure which form is preferred one is preferred as the teacher matters)

<em>Hope you understood and have a nice day!!</em>

6 0
3 years ago
Read 2 more answers
this is formula manipulation, I'd appreciate if the steps were provided. only respond if you know how to get the answer, thank y
marissa [1.9K]

Answer:

  1. r = 3V/(2πh²)
  2. h = 3V/b²
  3. r = 25/π cm ≈ 7.9577 cm
  4. w = 15 cm

Step-by-step explanation:

1. Multiply both sides of the equation by the reciprocal of the coefficient of r.

V\cdot\dfrac{3}{2\pi h^2}=r\\\\r=\dfrac{3V}{2\pi h^2}

__

2. Multiply both sides of the equation by the reciprocal of the coefficient of h.

V\cdot\dfrac{3}{b^2}=h\\\\h=\dfrac{3V}{b^2}

__

3. Solve the circumference formula for r, then substitute the given information.

C=2\pi r\\\\r=\dfrac{C}{2\pi}\qquad\text{divide by the coefficient of r}\\\\r=\dfrac{50\,\text{cm}}{2\pi}=\dfrac{25}{\pi}\,\text{cm}\approx 7.9577\,\text{cm}

__

4. Solve the perimeter formula for width, the substitute the given information and do the arithmetic.

P=2(L+W)\\\\\dfrac{P}{2}=L+W\qquad\text{divide by 2}\\\\\dfrac{P}{2}-L=W\qquad\text{subtract L}\\\\\dfrac{40\,\text{cm}}{2}-5\,\text{cm}=W=15\,\text{cm}

_____

In general, solving for a particular variable involves "undoing" what has been done to the variable, usually in the reverse order. In part 4, the variable W has L added and the sum is multiplied by 2. We "undo" those operations, last operation first, by dividing by 2 and subtracting L.

The properties of equality say you can do what you like to an equation as long as you do the same thing to both sides of the equation. So, when we say "divide by 2", we mean "divide both sides of the equation by 2." Likewise, "subtract L" means "subtract L from both sides of the equation."

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