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erik [133]
1 year ago
15

Find the area of each figure to the nearest tenth.

Mathematics
1 answer:
Levart [38]1 year ago
8 0

Answer:

20m, 10m, 30, 180, 290, 300, 20. i think.

Step-by-step explanation:

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ANSWER ASAP PLEASE!!!
Thepotemich [5.8K]

area of triangle = 1/2(3)(4) = 6 in^2

area of rectangle = 3 x 10 = 30 in^2

area of trapezoid = 1/2(3+5)(2) = 8 in^2


area of the figure: 6 in^2 + 30 in^2 + 8 in^2 = 44 in^2


answer

44 in^2

3 0
2 years ago
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Somebody please help me!
Ierofanga [76]

Method:

First place the replace of p and r using brackets.

= 3(6) + 11.7(7)

3 times 6 is 18 and 11.7 times 7 is 81.9

= 18 + 81.9

add one and one together you get

= 99.9

<em>hope </em><em>it </em><em>helps</em>

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3 years ago
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Answer:

140 will be his weight of Antony's weight

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2 years ago
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Use the Pythagorean Theorem to find an approximate value of x
kozerog [31]

Answer:

Step-by-step explanation:

Hypotenuse² =base² + altitude²

(3x + 4)² = (2x + 1)² + (3x)²

{Use (a+b)² = a² + 2ab + b²}

(3x)² + 2*3x+4 + 4² = (2x)² + 2*2x*1 + 1² + 9x²

9x² + 24x + 16 = 4x² + 4x + 1 + 9x²

9x² + 24x + 16 = 13x² + 4x + 1

0 = 13x² + 4x  + 1 - 9x²  - 24x - 16

13x² - 9x² + 4x - 24x +1 - 16 = 0

4x² - 20x - 15 = 0

a = 4 ; b =-20  ; c = -15

D = b² - 4ac  = (-20)² - 4*4*(-15) = 400 + 240 = 640

√D = √640 = 25.30

x=\dfrac{-b+\sqrt{D}}{2a} \ ; \ x=\dfrac{-b-\sqrt{D}}{2a}\\\\\\x=\dfrac{20+25.30}{2*4} \ ; \ x=\dfrac{20-25.30}{2*4}\\\\\\x=\dfrac{45.30}{8} \ ; \  x =\dfrac{-5.30}{8}\\\\

x = 5 .66   ; x = -0.66

Ignore x = -0.66 as length of a side cannot be negative

Answer : x = 5.66

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2 years ago
Complete the pattern
Mademuasel [1]
38 x 1 = 1
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