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3 years ago

Evaluate 0.53n + 5 when n= 3 and when n= -3

Mathematics

1 answer:

Dahasolnce [82]3 years ago

7 0

Answer:

1.59&-1.59

Step-by-step explanation:

.53(3)+5=1.59

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Find the product of the roots of the equation<br> xl-5x - 36 = 0

Marat540 [252]

Answer:

Step-by-step explanation:

Hello, I assume that you mean

$x^2-5x-36$

The product is -36.

$x_1 \text{ and } x_2 \text{ are the two roots, we can write}\\\\(x-x_1)(x-x_2)=x^2-(x_1+x_2)x+x_1\cdot x_2$

So in this example, it means that the sum is 5 and the product is -36.

Thank you

5 0

3 years ago

the area of a triangle is 384 square feet. If its base is 8 feet longer than its altitude, find the length of the base and the a

REY [17]

A=1/2bh
b=8+h
A=384

384=1/2(bh)
times 2
768=bh
sub
768=b(8+b)
768=8b+b^2
minus 768 both sides
0=b^2+8b-768
factor
0=(b-24)(b+32)
set to zero
b-24=0
b=24

b+32=0
minus 32
b=-32
false, legnths cannot be negative

b=24
24=8+h
minus 8
16=h

base=24ft
altetude=16ft

6 0

3 years ago

I REALLY NEED HELP PLEASE!!

disa [49]

part A)

$\bf \begin{array}{ccllll}
hours(x)&velocity(y)\\
-----&-----\\
1&6\\
3&2
\end{array}\\\\
-------------------------------\\\\$

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ 6}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ 2}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{2-6}{3-1}\implies \cfrac{-4}{2}\implies -2$

$\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-6=-2(x-1)\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-6=-2x+2\implies y=-2x+2+6\implies \boxed{y=-2x+8}$

part B)

well, we know y = -2x+8.... so.. what's the runner's velocity after 5hours? well, x = 5, thus y = -2(5) +8 ---> y = -2

to graph it, well, is a LINEar equation, meaning the graph is a LINE, and to graph a line, all you need is two points, and by now, you have more than two.. so graph it away.

7 0

3 years ago

Find the Number in Each Case

ipn [44]

It seems like you have the answer already. but heres how its calculated.
$\frac{100}{15} = \frac{?}{3}$
so the missing number is 20 **cross multiply 100 and 3 to get 300 then divide 15 into 300 to get 20**

$\frac{160}{100} = \frac{80}{?}$
so the missing number is 50
**cross multiply 100 and 80 to get 8000 then divide 160<span> into 8000 to get 50**</span>

6 0

3 years ago

Can you help me? Please

Anni [7]

9514 1404 393

Answer:

Step-by-step explanation:

For an even-index radical, ...

$\sqrt[n]{x^n}=|x|\qquad\text{n even}$

This lets us simplify the given expression as follows:

$\sqrt[4]{81x^6y^4}-|y|\sqrt[4]{x^6}-\sqrt[4]{16x^2}=\sqrt[4]{(3xy)^4x^2}-|y|\sqrt[4]{x^4x^2}-\sqrt[4]{2^4x^2}\\\\=3|xy|\sqrt[4]{x^2}-|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}=\boxed{2|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}}$

4 0

2 years ago