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2 years ago

Ou want to get an oil change every 4,000 miles. How many oil changes do you get in a year driving 1000 miles a month?

1 answer:

5 0

3.

1000 miles per month.
12 months in a year.
1000 × 12 = 12000 miles per year

Oil change every 4000 miles.
12000 ÷ 4000 = 3

Therefore 3 oil changes per year.

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What happens to the frequency as the period of a sinusoidal function increases

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Let T: Mmxn(R)Mmxn(R) be the function defined

alexandr402 [8]

Answer:

True. See the explanation and proof below.

Step-by-step explanation:

For this case we need to remeber the definition of linear transformation.

Let A and B be vector spaces with same scalars. A map defined as T: A >B is called a linear transformation from A to B if satisfy these two conditions:

1) T(x+y) = T(x) + T(y)

2) T(cv) = cT(v)

For all vectors $x,y \in V$ and for all scalars $c \in R$ . And A is called the domain and B the codomain of T.

Proof

For this case the tranformation proposed is t: $M_{mxn} (R) > M_{nxm} (R)$

Where $T(A) = A^T$

For this case we have the following assumption:

1) The transpose of an nxm matrix is an nxm matrix

And the following conditions:

2) $T(A+B) = (A+B)^T = A^T + B^T = T(A) + T(B)$

And we can express like this $T(A+B) =T(A) + T(B)$

3) If $A \in M_{mxn}(R)$ and $c \in R$ then we have this:

$T(cA) = (cA)^T = cA^T = cT(A)$

And since we have all the conditions satisfied, we can conclude that T is a linear transformation on this case.

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3 years ago

Gertrude takes out a $5,500 subsidized stafford loan, which must be paid back in ten years. gertrude will graduate four years af

Leno4ka [110]

The total amount of interest will Gertrude pay by the time the subsidized Stafford loan is repaid is $2094.80.

<h3>What is compound interest?</h3>

Compound interest is the amount charged on the principal amount and the accumulated interest with a fixed rate of interest for a time period.

The formula for the final amount with the compound interest formula can be given as,

$A=P\times\left(1+\dfrac{r}{n\times100}\right)^{nt}\\$

Here, A is the final amount (principal plus interest amount) on the principal amount P of with the rate<em> r </em>of in the time period of <em>t.</em>

Gertrude will graduate four years after taking out the loan. if the loan has an interest rate of 6.8%, compounded monthly, and Gertrude makes monthly payments.

Put the values in the above formula as,

$5500=P_{mt}\times\left(1-\dfrac{6.8}{12\times100}\right)^{-12\times10}\\P_{mt}=63.29$