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professor190 [17]
3 years ago
10

If f(x) = x^2 -1, what is the equation for f–1(x)?

Mathematics
2 answers:
schepotkina [342]3 years ago
5 0

Answer:

The inverse is ±sqrt(x+1)

Step-by-step explanation:

y = x^2 -1

Exchange x and y

x = y^2 -1

Solve for y

Add 1 for each side

x+1 = y^2-1+1

x+1 = y^2

Take the square root of each side

±sqrt(x+1) = sqrt(y^2)

±sqrt(x+1) = y

The inverse is ±sqrt(x+1)

sweet [91]3 years ago
5 0

Answer:

f^-1(x) = sqrt(x + 1)

Or

f^-1(x) = -sqrt(x + 1)

Step-by-step explanation:

y = x² - 1

x² = y + 1

x = +/- sqrt(y + 1)

Interswitch variables:

f^-1(x) = sqrt(x + 1)

Or

f^-1(x) = -sqrt(x + 1)

Where sqrt: square root

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Vsevolod [243]
Translation by h (right) and k (up)
g(x)=f(x-h)+k
=f(x-4)^2+2
so h=4, k=2
horizontal translation (to the right) is h=+4, but is shown as -4 for the translation value.

7 0
3 years ago
Find the value of y.y^2=169
wel

y^2=169

y = √169

y = + / - 13

Answer

y = -13 or y = 13

8 0
3 years ago
Write an equation for the line, given that m= 0 and the y - intercept (0, -2)
stich3 [128]

Remember that the slope intercept formula is:

y = mx + b

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so...

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^^^Plug these numbers into formula

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Hope this helped!

~Just a girl in love with Shawn Mendes

3 0
3 years ago
Read 2 more answers
Anyone have the answer for this
sergiy2304 [10]

\huge\bold{Given:}

Length of the base = 16 km.

Length of the hypotenuse = 34 km. \huge\bold{To\:find:}

✎ The length of the missing leg ''a".

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

The length of the missing leg "a" is\boxed{30\:km}.

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

Using Pythagoras theorem, we have

({perpendicular})^{2}  +  ({base})^{2}  =  ({hypotenuse})^{2}  \\ ⇢ {a}^{2}  +  ({16 \: km})^{2}  =  ({34 \: km})^{2}  \\ ⇢ {a}^{2}   + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 1156 \:  {km}^{2}  - 256 \:  {km}^{2}  \\ ⇢ {a}^{2}  = 900 \:  {km}^{2}  \\ ⇢a \:  =  \sqrt{900  \: {km}^{2} }  \\ ⇢a =  \sqrt{30 \times 30 \:  {km}^{2} }  \\ ⇢a = 30 \: km

\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}

\huge\bold{To\:verify :}

( {30 \: km})^{2}  +  ({16 \: km})^{2}  =(  {34 \: km})^{2}  \\ ⇝900 \:  {km}^{2}  + 256 \:  {km}^{2}  = 1156 \:  {km}^{2}  \\⇝1156 \:  {km}^{2}  = 1156 \:  {km}^{2}   \\ ⇝L.H.S.=R. H. S

Hence verified. ✔

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

7 0
2 years ago
What is 4x-8y=5 6x-12y=10
Anvisha [2.4K]
If it is a system of two unknowns:
1) 4x-8y=5 multiple by 3
2)6x-12y=10 multiple by -2
then
12x-24y=15
-12x+24y=-20
x and y equals 0, so
Answer: no solution
5 0
3 years ago
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