If f(x) = x^2 -1, what is the equation for f–1(x)?

Mathematics

2 answers:

schepotkina [342]4 years ago

5 0

Answer:

The inverse is ±sqrt(x+1)

Step-by-step explanation:

y = x^2 -1

Exchange x and y

x = y^2 -1

Solve for y

Add 1 for each side

x+1 = y^2-1+1

x+1 = y^2

Take the square root of each side

±sqrt(x+1) = sqrt(y^2)

±sqrt(x+1) = y

The inverse is ±sqrt(x+1)

sweet [91]4 years ago

5 0

Answer:

f^-1(x) = sqrt(x + 1)

f^-1(x) = -sqrt(x + 1)

Step-by-step explanation:

y = x² - 1

x² = y + 1

x = +/- sqrt(y + 1)

Interswitch variables:

f^-1(x) = sqrt(x + 1)

f^-1(x) = -sqrt(x + 1)

Where sqrt: square root

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Can someone please help mee i need the exact answer(30 points will give brainliest!!!)

Bas_tet [7]

The domain of the given graph is [−3, ∞) and the range is (−∞, 4].

We need to find the domain and range of the given graph.

<h3>What are the domain and range of the function?</h3>

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values that it can take.

We can observe that the graph extends horizontally from −3 to the right without a bound, so the domain is [−3, ∞). The vertical extent of the graph is all range values 4 and below, so the range is (−∞, 4].