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3 years ago

If f(x) = x^2 -1, what is the equation for f–1(x)?

Mathematics

2 answers:

schepotkina [342]3 years ago

5 0

Answer:

The inverse is ±sqrt(x+1)

Step-by-step explanation:

y = x^2 -1

Exchange x and y

x = y^2 -1

Solve for y

Add 1 for each side

x+1 = y^2-1+1

x+1 = y^2

Take the square root of each side

±sqrt(x+1) = sqrt(y^2)

±sqrt(x+1) = y

The inverse is ±sqrt(x+1)

sweet [91]3 years ago

5 0

Answer:

f^-1(x) = sqrt(x + 1)

f^-1(x) = -sqrt(x + 1)

Step-by-step explanation:

y = x² - 1

x² = y + 1

x = +/- sqrt(y + 1)

Interswitch variables:

f^-1(x) = sqrt(x + 1)

f^-1(x) = -sqrt(x + 1)

Where sqrt: square root

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Korvikt [17]

Answer:

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or, 1meters/second = 1/0.45

1m/s = 2.22222222222

Step-by-step explanation:

Then,

72.0 meters/second = 72.0*2.22222222222

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3 years ago

Which of the points satisfy the linear inequality graphed here?

SOVA2 [1]

Only
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2 years ago

In a random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand. C

horrorfan [7]

Answer:

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

Step-by-step explanation:

Step(i):-

Given sample size 'n' =300

Given data random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.

Given sample proportion

$p^{-} = \frac{x}{n} = \frac{182}{300} =0.606$

level of significance = 90% or 0.10

Z₀.₁₀ = 1.645

90% confidence interval for the proportion is determined by

$(p^{-} - Z_{0.10}\sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.10}\sqrt{\frac{p(1-p)}{n} })$

$(0.6066 - 1.645\sqrt{\frac{0.6066(1-0.6066)}{300} } ,0.6066+1.645\sqrt{\frac{0.6066(1-0.6066)}{300} })$

(0.6066 - 0.0463 ,0.6066 + 0.0463)

(0.5603,0.6529)

final answer:-

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

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3 years ago

Which of the following data sets contain an outlier?

AURORKA [14]

Answer:

Step-by-step explanation:

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3 years ago