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Ivenika [448]
3 years ago
12

Silicon is produced for the chemical and electronics industries by the following reactions. Give the balanced equation for each

reaction. (Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed, leave it blank.)
a. SiO2 (s) + C(s) + Si(s) + CO(g) SiO2(s) + C(s) Si(s) + CO(g)
b. Liquid silicon tetrachloride is reacted with very pure solid magnesium, producing solid silicon and solid magnesium chloride. + +
c. Na2 SiF6(s) + Na(s) + Si(s) + NaF(s) Na2SiF6(s) + Na(s) Si(s) + NaF(s)
Chemistry
1 answer:
Sav [38]3 years ago
7 0

Answer:

Explanation:

The equations in each option are confusing (repeated) but understandable

Balancing a chemical equation means the same number of individual and overall atoms on the reactant side is equal to the same number of individual and overall atoms on the product side. This is based on the law of conservation of matter which states that matter can neither be created nor destroyed, hence the no atom must be unaccounted for on any side.

The balancing of these equations seem to test the knowledge of a particular trick in balancing of equation - which will be highlighted as the equation is balanced

(a) To balance

SiO₂(s) + C(s) ⇒ Si(s) + CO(g)

The balanced equation will be

SiO₂(s) + 2C(s) ⇒ Si(s) + 2CO(g)

NOTE: The best way to address equations like this to balance the uniatomic element last.

(b) SiCl₄(l) + Mg(s) ⇒ Si(s) + MgCl₂(s)

The balanced equation will be

SiCl₄(l) + 2Mg(s) ⇒ Si(s) + 2MgCl₂(s)

NOTE: As noted earlier, the uniatomic  molecule should be balanced last

(c) To balance

Na₂SiF₆(s) + Na(s) ⇒ Si(s) + NaF(s)

The balanced equation will be

Na₂SiF₆(s) + 4Na(s) ⇒ Si(s) + 6NaF(s)

NOTE: As noted earlier, the uniatomic  molecule should be balanced last

Please, always sum the number of individual and overall atoms on both sides when you are done answering questions like this just to be sure.

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We will assume that the question is discussing 1.000 atm of N₂ initially. The question is discussing diffusion rates of two gases and asks us to identify the species. We can use Graham's Law to attempt this problem with the following formula:

Rate₁/Rate₂ = sqrt(M₂/M₁)

We are told that the N₂ is 3.55 times as fast as the unknown species, so rate 1 = 3.55 and rate 2 = 1. We know the molecular weight of N₂ as 28 g/mol. Now we can use the equation above to solve for the molecular weight of the unknown, M₂:

3.55/1 = sqrt(M2/28)
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4 years ago
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Answer:

The diluted solution is 0.65 M

Explanation:

Dilution formula to solve the problem is:

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We can also make a rule of three though.

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So in 25 mL we have (25 . 13.1 ) / 1000 = 0.327 moles of HNO₃

This moles are also in 0.500 L of diluted solution, the new molarity will be:

0.327 mol / 0.5L = 0.65 M

Molarity of diluted solution must be always lower than concentrated solution, otherwise the excersise is wrong.

If we replace in the formula

13.1 M . 25 mL = 500 mL . M diluted

M diluted = 13.1 m . 25 mL / 500 mL = 0.65 M

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