Answer:
let height of ||g be 'b', then base of ||g be 3b.
area of ||g=base×height
75cm
2
=3b×b
b
2
=25
b=5cm, therefore height =5cm
Answer:
(2*n)+9=n-30
Step-by-step explanation:
I'm not sure but I think that is the equation
A) How high up the wall does it reach?
Use the Pythagorean theorem
Height^2 + Base^2 = Hyp^2
H^2+ 2^2 = 4^2 Subtract the 2^2 from both sides
H^2 = 4^2 -2^2 Multiply the square roots of both the numbers
H^2= 16 - 4
H^2 = 12
H= sqrt(12) m
Hope this helps
The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.
We want angle x, which is opposite the side of length 39.
Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x
or 1521 = 3481 + 1296 - 2(36)(59) cos x
Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x
-3256 = -4248cos x
-3256
Then: cosx = --------------- = 0.766
-4248
Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)
Answer:
Step-by-step explanation:
