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3 years ago

Which of these is not a formula that can be used to find the volume of a cube

Mathematics

1 answer:

Kay [80]3 years ago

4 0

Answer:

Step-by-step explanation:

Base times height

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Simplify 2- 5/8 and -2 3/5 A. -6 33/40 B. 4- 3/8 C. 4 3/8 d. 6 33/40

worty [1.4K]

Answer:

Step-by-step explanation:

Convert mixed fraction to improper fraction.

$-2\dfrac{5}{8}*(-2\dfrac{3}{5})=\dfrac{-21}{8}*\dfrac{-13}{5}\\$

$=\dfrac{(-21)*(-13)}{8*5}\\\\\\=\dfrac{273}{40}\\\\=6\dfrac{33}{40}$

4 0

2 years ago

Which is more money: 50% of the sum of $150 and $50 or 1.5 times

lidiya [134]

50 is tens and 150 is hundreds

4 0

3 years ago

Read 2 more answers

Question 4 please provide explanation for question

Artist 52 [7]

Answer:

Step-by-step explanation:

We need to find a equation that is where the domain is all real numbers and the range is all real numbers greater than -3

A square root function cannot equal to all real numbers because we cant take the square root of a negative number. so B and C are already wrong.
A cubic function range is all real numbers. so y can be greater than -3 but it would also include. values lesser than -3. so D is Wrong.

A is right, the domain of a absolute value function is all real numbers. The range of a absolute value is all numbers greater than or equal to zero but if we subtract 3, it changes into all real numbers greater than or equal to -3

3 0

3 years ago

Given csc(A) = 65/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational

charle [14.2K]

Answer:

$secA = \frac{65}{63}$

Step-by-step explanation:

$cosec A = \frac{65}{16}\\\\sin A = \frac{1}{cosecA} = \frac{16}{65}\\\\cos^2 A = 1 - sin^2 A$

$= 1 - (\frac{16}{65})^2\\\\=\frac{4225-256}{4225}\\\\=\frac{3969}{4225}\\$

$cos A = \sqrt{\frac{3696}{4225}} = \frac{63}{65}$

$secA = \frac{1}{cosA} = \frac{65}{63}$

7 0

2 years ago

Thirty five percent of the employees in a company have managerial positions, and 67 percent of the employees in the company have

seraphim [82]

Answer:

49% of employees who either have MBA or are managers.

Step-by-step explanation:

We are given the following information in the question:

P(Managerial) = 35% = 0.035

P(MBA) = 67% = 0.67

$P(\text{Managerial} \cap \text{MBA}) = 53\% = 0.53$

We have to find the probability of employees who either are have MBA or are managers.

According to De-Morgan's law:

$P(\text{Managerial} \cup \text{MBA}) = P(\text{Managerial}) + P(\text{MBA}) - P(\text{Managerial} \cap \text{MBA}) \\P(\text{Managerial} \cup \text{MBA}) = 0.35 + 0.67 - 0.53 = 0.49$

Thus, around 49% of employees who either have MBA or are managers.

7 0

3 years ago