Answer:
![MA=\frac{F_l}{F_e}>1](https://tex.z-dn.net/?f=MA%3D%5Cfrac%7BF_l%7D%7BF_e%7D%3E1)
Explanation:
The mechanical advantage with a shorter lever will always be greater than 1.
It is so because with a longer effort arm we need to apply lesser force to lift a unit mass which is at a shorter distance from the fulcrum. This is in accordance with the conservation of moments.
![F_e\times d_e=F_l\times d_l](https://tex.z-dn.net/?f=F_e%5Ctimes%20d_e%3DF_l%5Ctimes%20d_l)
where:
force on the effort arm
force on the load arm
are the lengths of load effort arm and load arm respectively.
So, one factor balances the other keeping the product of the two constant.
And we know that mechanical advantage is :
![MA=\frac{F_l}{F_e}](https://tex.z-dn.net/?f=MA%3D%5Cfrac%7BF_l%7D%7BF_e%7D)
Answer:
1) F = 8.789 10² N, 2) F = 1.5 10⁴ N
Explanation:
We can solve this exercise using Coulomb's law
F =![k \frac{q_1q_2}{r^2}](https://tex.z-dn.net/?f=k%20%5Cfrac%7Bq_1q_2%7D%7Br%5E2%7D)
Knowing that charges of the same sign repel
let's apply this equation to our case
1) the charges are q = - 0.0025 C and the distance between them r = 8 m
we calculate
F = 9 10⁹ 0.0025 0.0025 /8²
F = 8.789 10² N
as the two charges are of the same sign the force is repulsive
2) q₁ = -0.004C and q₂ = -0.003 C with a distance of r = 3.0 m
we calculate
F = 9 10⁹ 0.004 0.003 / 3²
F = 1.5 10⁴ N
Answer:
The exergy is 279.77 kJ/kg
The exergy of the exhaust gases is 143.24 kJ/kg
Explanation:
the step by step is in the image