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Naily [24]
4 years ago
14

what is a possible unit for the product VI, where V is the potential difference across a resistor and I is the current through t

he same resistor?
Physics
1 answer:
liq [111]4 years ago
5 0
Recall this equation for a device in a direct current circuit:
P = IV
P is the power dissipated by the device, I is the current through the device, and V is the voltage drop of the device.

If we choose to use the ampere as the unit of current and the volt as the unit of voltage, then the product of the current and the voltage will give the power with watts as the unit.
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A light-year is the distance light travels in one year (at speed = 2.998 × 108 m/s). (a) how many meters are there in 11.0 light
larisa [96]
<span>The answers are as follows:

(a) how many meters are there in 11.0 light-years?

11.0 light years ( 365 days / 1 year ) ( 24 h / 1 day ) ( 60 min / 1 h ) ( 60 s / 1 min ) ( 2.998x10^8 m/s ) = 1.04x10^17 m

(b) an astronomical unit (au) is the average distance from the sun to earth, 1.50 × 108 km. how many au are there in 11.0 light-years?

1.04x10^17 m ( 1 au / </span>1.50 × 10^8 km <span>) ( 1 km / 1000 m) = 693329.472 au

(c) what is the speed of light in au/h? au/h

</span>2.998 × 10^8 m/s ( 1 au / 1.50 × 10^8 km ) ( 1 km / 1000 m) ( 3600 s / 1 h ) = 7.1952 au/h

8 0
3 years ago
At a depth of 10.9 km, the Challenger Deep in the Marianas Trench of the Pacific Ocean is the deepest site in any ocean. Yet, in
bearhunter [10]

Answer:

P = 1.09 \times 10^8 Pa

Explanation:

As we know that the pressure inside the liquid level is given as

P = \rho g h + P_o

here we have

\rho = 1024 kg/m^3

h = 10.9 km

also we know that

P_o = 1.01 \times 10^5 Pa

now we have

P = (1.01 \times 10^5) + (1024)(9.81)(10.9 \times 10^3)

P = 1.09 \times 10^8 Pa

8 0
3 years ago
How does radiation differ from conduction? (4 points)
mario62 [17]
The difference between radiation and conduction is that radiation is described as he transfer of heat energy by electromagnetic waves without involving particles. Conduction is described as the flow of heat from one solid to another, using a hot knife as an example.
7 0
3 years ago
What two scientists played a big role in studying the origins of the universe?
Bess [88]
An astronomer and also a cosmologist

5 0
3 years ago
A typical car has 16 L of liquid coolant circulating at a temperature of 95 ∘C through the engine's cooling system. Assume that,
amm1812

Answer:

\Delta V=0.0592\ L

Explanation:

Given:

  • Initial temperature of the coolant, T_f=95^{\circ}C
  • final temperature of the coolant, T_f=105^{\circ}C
  • total volume of the coolant, V_c=16\ L
  • coefficient of volume expansion for coolant, \beta_c=410\times 10^{-6}\ ^{\circ}C^{-1}
  • volume of Al radiator, V_a=2\ L
  • volume of steel radiator,  V_s=14\ L

<u><em>We have:</em></u>

coefficient of volume expansion for Aluminium, \beta_a=75\times 10^{-6}\ ^{\circ}C^{-1}

coefficient of volume expansion for steel, \beta_a=35\times 10^{-6}\ ^{\circ}C^{-1}

<u>Now, change in volume of the coolant after temperature rises:</u>

\Delta V_c=V_c.\beta_c.\Delta T

\Delta V_c=16\times 410\times 10^{-6}\times (105-95)

\Delta V_c=0.0656\ L

<u>Now, volumetric expansion in Aluminium radiant:</u>

\Delta V_a=V_a.\beta_a.\Delta T

\Delta V_a=2\times 75\times 10^{-6}\times (105-95)

\Delta V_a=0.0015\ L

<u>Now, volumetric expansion in steel radiant:</u>

\Delta V_s=V_s.\beta_s.\Delta T

\Delta V_s=14\times 35\times 10^{-6}\times (105-95)

\Delta V_s=0.0049\ L

∴Total extra accommodation volume created after the expansion:

V_X=\Delta V_s+\Delta V_a

V_X=0.0049+0.0015

V_X=0.0064\ L

Hence, the volume that will overflow into the small reservoir will be the volume of coolant that will be extra after the expanded accommodation in the radiator.

\Delta V=\Delta V_c-\Delta V_X

\Delta V=0.0656-0.0064

\Delta V=0.0592\ L

3 0
3 years ago
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