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tresset_1 [31]
3 years ago
10

Using the Time Series Data for the US Nuclear Electric Power Production, calculate the exponential smoothing forecasts for 2005

through 2010 using alpha equals 0.2. Find the forecast error for each time period. If there is n
Mathematics
1 answer:
Marat540 [252]3 years ago
5 0

Answer:

????????????

I don't know

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(8y²)(-3x²y²)(2/3xy⁴)<br><br> HELP PLEASEEEEEEEE
IRINA_888 [86]

Step-by-step explanation:

1 Remove parentheses.

8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}

8y

2

×−3x

2

y

2

×

3

2

xy

4

2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

b

a

×

d

c

=

bd

ac

.

\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}

3

8y

2

×−3x

2

y

2

×2xy

4

3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(8×−3×2)y

2

y

2

y

4

x

2

x

4 Simplify 8\times -38×−3 to -24−24.

\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(−24×2)y

2

y

2

y

4

x

2

x

5 Simplify -24\times 2−24×2 to -48−48.

\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

−48y

2

y

2

y

4

x

2

x

6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}

3

−48y

2+2+4

x

2+1

7 Simplify 2+22+2 to 44.

\frac{-48{y}^{4+4}{x}^{2+1}}{3}

3

−48y

4+4

x

2+1

8 Simplify 4+44+4 to 88.

\frac{-48{y}^{8}{x}^{2+1}}{3}

3

−48y

8

x

2+1

9 Simplify 2+12+1 to 33.

\frac{-48{y}^{8}{x}^{3}}{3}

3

−48y

8

x

3

10 Move the negative sign to the left.

-\frac{48{y}^{8}{x}^{3}}{3}

−

3

48y

8

x

3

11 Simplify \frac{48{y}^{8}{x}^{3}}{3}

3

48y

8

x

3

to 16{y}^{8}{x}^{3}16y

8

x

3

.

-16{y}^{8}{x}^{3}

−16y

8

x

3

Done

6 0
2 years ago
Jerry is a judge. he hears 5 cases every 2 3/8 hours how many cases does he haer per hour
vampirchik [111]

Answer:

2 2/19

Step-by-step explanation:

5 cases in 2 3/8 hours

The unit rate of cases per hour is calculated by dividing the number of cases by the number of hours.

5/(2 3/8) = 5/(19/8) = 5 * 8/19 = 40/19 = 2 2/19

7 0
3 years ago
Read 2 more answers
The problem of matching aircraft to passenger demand on each flight leg is called the flight assignment problem in the airline i
Darina [25.2K]

Answer:

Step-by-step explanation:

Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42

Let X be the no of passengers who report

X is N(132, 42)

Or Z is \frac{x-132}{42}

a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.

the probability that the demand will exceed the capacity of this airplane

=P(X>183) = P(Z>1.21) =

=0.5-0.3869\\=0.1131

b)  the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers

=P(80\leq x\leq 200)\\= P(-1.23\leq z\leq 1.62)\\

=0.4474+0.3907

=0.8381

c) the probability that the demand for this flight will be less than 100 passengers

=P(x

d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers

=P(Z>c)=0.03\\c=1.88\\X=132+1.88(42)\\=210.96

e) 79th percentile of this distribution

=132+0.81(42)\\= 166.02

7 0
3 years ago
show me how to work this problem, point A(7,9)is dilated from the origin by scale factor r was= 6. what are the coordinates of p
frutty [35]

If the point is dilated from the origin by a scale factor of 6

Then the coordinates of point A becomes

A( 6x7 , 6x9)

A_{0,6}(7,9)=(42,\text{ 54)}

6 0
1 year ago
Can someone help me I’ll give u 20 points
mamaluj [8]

Answer:

#1. X=3 and #2. Y=9

Step-by-step explanation:

Glad i could help, give me a follow, so if you need help with any other question, im here.

3 0
3 years ago
Read 2 more answers
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