Question

Limited time . 10 points

Answer 1

Answer:

Therefore the value of x is

$x=1\pm\sqrt{19}i$

Step-by-step explanation:

Given:

$x^{2}+20=2x$ which is

$x^{2}-2x+20=0$

To Find:

x = ? using Quadratic Formula

Solution:

For a Quadratic Equation ax² + bx + c = 0 , Formula Method is given as

$x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

On Comparing with above we get

$a=1\\b=-2\\c=20$

Substituting a , b , c in Formula method we get

$x=\dfrac{-(-2)\pm\sqrt{(-2)^{2}-4(1)(20)}}{2\times 1}\\\\x=\dfrac{2\pm\sqrt{-76}}{2}\\\\x=\dfrac{2\pm2\sqrt{19}i}{2}\\Dividing\ by\ 2\ we\ get\\\\x=1 \pm\sqrt{19}i$

Therefore the value of x is

$x=1\pm\sqrt{19}i$