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trapecia [35]
3 years ago
8

Point C has a _____ abscissa and a _____ ordinate.

Mathematics
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

i think its b but im not that sure

Step-by-step explanation:

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Helppppppppppppp plsssssssssssssssss
Helen [10]

Answer:

PQR = 40

QNP = 60

Step-by-step explanation:

PQR = 180 - (60 + 80)

QNP = 180 - (40 + 80)

4 0
2 years ago
Please help
shtirl [24]

Answer:

Step-by-step explanation:

The slope of the line in question is the same as the slope of the line parallel to it. Using y = mx + b, where m is the slope, we find the slope of our line is -3.

Using the pt-slope form, y - y1 = m( x - x1), we get y - (-1) = -3( x - 2) or y + 1 = -3x + 6. Which leads us to y = -3x + 5. QED

4 0
3 years ago
Image. please help!!​
dem82 [27]

Answer:

Step-by-step explanation:

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5 0
3 years ago
Can someone help me please
Yuliya22 [10]

Answer:

B

Step-by-step explanation:


3 0
3 years ago
line k has a slope of -5. line j is perpendicular to line k and passes though the point (5,9) create the equation for line j
Anna71 [15]

Answer:

y = 1/5x + 8

Step-by-step explanation:

The first thing you should know is that the slope of a perpendicular line is the opposite reciprocal. So, the slope of line j is 1/5. This is your current equation: y=1/5x + b. Plug in your coordinate to the equation, it should look like this: 9=1/5(5)+ b. 1/5 times 5 equals 1, so this is what it should look like: 9=1 + b. Subtract 1 from both sides to get 8 = b. Go back to your original equation and plug in 8 to b. This is your final equation: y = 1/5x + 8. Hope this helped!

3 0
3 years ago
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