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1 year ago

Hey can someone help?

Mathematics

2 answers:

Ronch [10]1 year ago

4 0

The value of the given variable x in the missing angles is; x = 12°

<h3>How to find alternate Angles?</h3>

Alternate angles are defined as the angles that occur on opposite sides of the transversal line and as such have the same size. There are two different types of alternate angles namely alternate interior angles as well as alternate exterior angles.

Now, from the question, we can see that ∠4 and ∠6 suit the definition of alternate angles and as such we can say that they are both congruent.

Since ∠4 = (8x + 4)° and ∠6 = (6x + 28)°, then we can say that;

(8x + 4)° = (6x + 28)°

Rearranging this gives us;

8x - 6x = 28 - 4

2x = 24

x = 24/2

x = 12°

Read more about Alternate Angles at; brainly.com/question/24839702

#SPJ1

KATRIN_1 [288]1 year ago

3 0

Answer:

x = 8

Step-by-step explanation:

When two line are parallel, alternate angles are equal to each other.

Therefore,

<4 = <6

8x + 4 = 5x + 28

Now, let us solve the above equation and find the value of x.

<em>First, subtract 5x from both sides. </em>

8x - 5x + 4 = 28

3x + 4 = 28

<em>Subtract 4 from both sides. </em>

3x = 28 - 4

3x = 24

<em>Divide both sides by 3.</em>

x = 8

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Answer:

The equation of required line is: $\mathbf{5x-8y+34=0}$

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to $5x-8y+12=0$ and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line $5x-8y+12=0$ to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: $y=mx+b$ where m is slope.

$5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}$

So, the slope m = 5/8

The slope of required line is $m=\frac{5}{8}$

Now finding y-intercept using slope $m=\frac{5}{8}$ and point(-2,3)

$y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}$

So, the equation of required line having slope $m=\frac{5}{8}$ and y-intercept $b=\frac{17}{4}$

$y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8} \\8y=5x+34\\5x-8y+34=0$

So, The equation of required line is: $\mathbf{5x-8y+34=0}$

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