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3 years ago

Tom is 13 years old Brad is 10 years old which number sentence can be used to find how much older Tom is than Brad

Mathematics

1 answer:

ivanzaharov [21]3 years ago

3 0

Answer: Tom is 3 years old then Brad

Step-by-step explanation:

Tom's age minus Brad's age.

13 - 10 = 3

I hope this helps you!

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Find the equation of the line that passes through (−4, 8) with slope −3. Write in slope-intercept form. F y = – 3x – 4 G y = – 4

storchak [24]

Answer: y=-3x-4

Step-by-step explanation:

Since we know slope, we can plug it into slope-intercept form to find the y-intercept by using the given points,

y=-3x+b

8=-3(-4)+b

8=12+b

b=-4

Now that we know the y-intercept, we can complete the slope-intercept form.

y=-3x-4

8 0

3 years ago

According to Nielsen Media Research. of all the U.S. households that owned at least one television set, 83% had two or more sets

Rudik [331]

Answer:

The proportion of U.S. households that owned two or more televisions is 83%.

Step-by-step explanation:

To determine whether the proportions of U.S. households that owned two or more televisions is less than 83% or not let us perform a hypothesis test for single proportion.

Assumptions:

The sample size (n) selected by the local cable company is 300 which is quite large. Then according to the Central limit theorem the sampling distribution of sample proportion follows a normal distribution with mean p and standard deviation $\sqrt{\frac{p(1-p)}{n} }$ .

Since the sampling distribution of sample proportions follows a normal distribution use the z-test for one proportion to perform the test.

The hypothesis is:

$H_{0}$ : The proportion of U.S. households that owned two or more televisions is 83%, i.e. $p=0.83$

$H_{1}$ :The proportion of U.S. households that owned two or more televisions is less than 83%, i.e. $p< 0.83$

Decision Rule:

At the level of significance α = 0.05 the critical region for a one-tailed z-test is:

$\\ Z\leq -1.645\\$

**Use the z table for the critical values.

So, if $\\ Z\leq -1.645\\$ the null hypothesis will be rejected.

Test statistic value:

$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

Here $\hat{p}$ is the sample proportion.

Compute the value of $\hat{p}$ as follows:

$\hat{p}=\frac{X}{n} \\=\frac{240}{300}\\ =0.80$

Now compute the value of the test statistic as follows:

$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}\\=\frac{0.80-0.83}{\sqrt{\frac{0.83*(1-0.83)}{300} } } \\=-1.383$

The test statistic is -1.383 which is more than -1.645.

Thus, the test statistic lies in the acceptance region.

Hence we fail to reject the null hypothesis.

Conclusion:

At 0.05 level of significance we fail to reject the null hypothesis stating that the proportion of U.S. households that owned two or more televisions is 83%.

6 0

3 years ago

Mary spent $8 of the $40 that she had. What is this as a fraction?

irakobra [83]

Answer:

8/40 is the correct answer

4 0

4 years ago

Select all of the possible degrees of this polynomial function 2 3 4 5

Dafna1 [17]

Answer:

it there n image