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miskamm [114]
3 years ago
11

Fill in the missing reasons (one for each step). Given: 3x – 6y = 27; x = 5 Prove: -2 = y

Mathematics
1 answer:
JulsSmile [24]3 years ago
5 0

Answer:

a. Given,

b. Substitution

c. Subtraction of equality

d. Division of equality

e. Symmetric property of equality

Step-by-step explanation:

Given expression,

3x - 6y = 27; x = 5

By substituting x = 5,

3(5) - 6y = 27

15 - 6y = 27

By subtraction property of equality,

-6y = 12

Division property of equality,

y = -2

By symmetric property of equality,

-2 = y

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Help please!<br> Thank you
Margarita [4]

Answer:

G

Step-by-step explanation:

Red marble probably currently: 12/32 = 3/8

Guess and check (using the multiple choice answers):

F: 12 + 13 / 32 + 13 = 25/45 = 5/6; does not equal 3/5

G: 12 + 18 / 32 + 18 = 30/50 = 3/5; does equal 3/5

H: 12 + 28 / 32 + 28 = 40/60 = 2/3; does not equal 3/5

J: 12 + 32 / 32 + 32 = 44/64 = 11/16; does not equal 3/5

K: 12 + 40 / 32 + 40 = 52/72 = 13/18; does not equal 3/5

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3 years ago
Find the valie of x (please help
sweet-ann [11.9K]
The answer is 3 because Pythagorean triplets consist of 3,4 and 5.
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3 years ago
John wants to send a letter to peter who lives on tesla street john does not remember the house number however he knows that it
Serggg [28]

Answer: 137 letters.

Step-by-step explanation:

The data is:

The number has 4 digits.

The number is a multiple of 5

The number is a multiple of 7

The last digit is a 0.

Then, let's find all the possible numbers that met these conditions.

Our number can be formed with 4 digits, A, B, C and D.

D is the last one, so we have  D = 0.

So the number is: ABC0

We know that all the numbers that end with 0 are multiples of 5, so that condition does not matter.

Now, a number is divisible by 7 if:

Take the last digit of the number, double it and subtract it to the remaining number, if the result is multiple of 7, then the initial number is a multiple of 7.

In this case the last digit is 0, so when we double it and subtract it, we actually are not changing the other 3 digits.

Then we have that:

ABC must be a multiple of 7.

So now our problem reduces to find the number of 3-digit numbers that are multiples of 7.

The first multiple of 7 that has 3 digits is:

7*15 = 105.

And the largest possible 3 digit number is 999, now let's try to divide it by 7 to see if this is also a multiple of 7.

999/7 = 142.7

the quotient is not integer, so 999 is not a multiple of 7.

The next option is 998, we can do the same here:

998/7 = 142.6

And so on, we will find that the largest 3 digit multiple of 7 is:

994, such that:

7*152=994.

Then we have:

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Largest: 7*152 = 994.

Then the number of multiples of 7 between 999 and 100 will be equal to the difference between the quotients between the multples and 7.

105/7 = 15

994/7 = 152

152 - 15 =  137

So we have 137 multiples of 7 with 3 digits.

Then we have 137 4-digit numbers, that end with a zero and also are divisible by 5 and 7.

So John must send 137 letters if he wants to be shure that Peter will get the card.

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