<u>w</u><u>=</u><u>-</u><u>1</u><u>.</u><u>5</u>
<u>w</u><u>=</u><u>2</u>
Answer:
Solution given:
again
keep square root alone
solve subtraction of 7-2
Squaring on both side
2w²-19w+31=5²-2*5*2w+4w²
take terms one side
2w²-19w+31-25+20w-4w²=0
-2w²+w+6=0
2w²-w-6=0
doing middle term factorisation
2w²-(4-3)w-6=0
2w²-4w+3w-6=0
take common from each two term
2w(w-2)+3(w-2)=0
(w-2)(2w+3)=0
either
w=2
or
W=-3/2=-1.5
The velocity v and maximum height h of the water being pumped into the air are related by the equation
v=
where g = 32
(a) To find the equation that will give the maximum height of the water , solve the equation for h
v=
Take square root on both sides
= 2gh
Divide by 2g on both sides
= h
So maximum height of the water h =
(b) Maximum height h= 80
velocity v= 75 ft/sec
Given g = 32
h =
h =
h= 87.89 ft
The pump withe the velocity of 75 ft/sec reaches the maximum height of 87.89 feet. 87.86 is greater than the maximum height 80 feet.
So the pump will meet the fire department needs.