Answer:
Case-based reasoning.
Explanation:
A database management system (DBMS) can be defined as a collection of software applications that typically enables computer users to create, store, modify, retrieve and manage data or informations in a database. Generally, it allows computer users to efficiently retrieve and manage their data with an appropriate level of security.
A data dictionary can be defined as a centralized collection of information on a specific data such as attributes, names, fields and definitions that are being used in a computer database system.
In a data dictionary, data elements are combined into records, which are meaningful combinations of data elements that are included in data flows or retained in data stores.
This ultimately implies that, a data dictionary found in a computer database system typically contains the records about all the data elements (objects) such as data relationships with other elements, ownership, type, size, primary keys etc. This records are stored and communicated to other data when required or needed.
Basically, when a database management system (DBMS) receives data update requests from application programs, it simply instructs the operating system installed on a server to provide the requested data or informations.
Case-based reasoning is a problem-solving technique where each problem in a database is stored with a description and keywords that identify it. It is typically based on cognitive science and artificial intelligence.
Answer:
#include <iostream>
using namespace std;
double DrivingCost(int drivenMiles,double milesPerGallon,double dollarsPerGallon)
{
double dollarsperMile=dollarsPerGallon/milesPerGallon;//calculating dollarsperMile.
return dollarsperMile*drivenMiles;//returning thr driving cost..
}
int main() {
double ans;
int miles;
cout<<"Enter miles"<<endl;
cin>>miles;
ans=DrivingCost(miles,20.0,3.1599);
cout<<ans<<endl;
return 0;
}
Output:-
Enter miles
10
1.57995
Enter miles
50
7.89975
Enter miles
100
15.7995
Explanation:
In the function first I have calculated the dollars per mile and after that I have returned the product of dollarspermile and driven miles.This will give the cost of the Driving.
Explanation:
no linda is the core member not rhe project
Answer:
See explaination for the code
Explanation:
def wordsOfFrequency(words, freq):
d = {}
res = []
for i in range(len(words)):
if(words[i].lower() in d):
d[words[i].lower()] = d[words[i].lower()] + 1
else:
d[words[i].lower()] = 1
for word in words:
if d[word.lower()]==freq:
res.append(word)
return res
Note:
First a dictionary is created to keep the count of the lowercase form of each word.
Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.
Finally the res list is appended.
