Answer:
Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.
Step-by-step explanation:
We find the components of the forces in x-y-z
Force of Jack in z =F₁z=90.5 N in direction (+z)
Force of Jill in x = F₂x= -82.3*cos45°= - 58.19 N (-x)
Force of Jill in y =F₂y=-82.3*sin45°= + 58.19 N (+y)
Force of Jane in x =F₃x=125*cos45°= + 88.4 N (+x)
Force of Jane in y =F₃y=125*sin45°= + 88.4 N (+y)
Calculating of the components of the net force the people exert on the donkey.
Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)
Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)
Fnz =F₁z=90.5 N (+z)
Calculating of the magnitude of the net force the people exert on the donkey.
Answer:
53.08 ft
Step-by-step explanation:
The pressure at the bottom of the tank, P = ρgh where ρ = density of water = 1000 kg/m³, g = acceleration due to gravity = 9.8 m/s² and h = depth of water in tank.
Since the pressure at the bottom of the tank, P = ρgh, making h subject of the formula, we have
h = P/ρg
Since P = 23 psig = 23 × 1 psig = 23 × 6894.76 Pa = 158579.48 Pa
Substituting the values of the other variables into h, we have
h = P/ρg
h = 158579.48 Pa/(1000 kg/m³ × 9.8 m/s²)
h = 158579.48 Pa/(9800 kg/m²s²)
h = 16.18 m
h = 16.18 × 1 m
h = 16.18 × 3.28 ft
h = 53.08 ft
The lengths of the line segments are summarized in the following list:
- DF = 3
- DE = 8 / 3
- FG = 3
- FH = 9 / 2
- GH = 3 / 2
- EH = - 11 / 6
<h3>How to calculate the length of a line segment based on point set on a number line</h3>
Herein we have a number line with five points whose locations are known. The length of each line segment is equal to the arithmetical difference of the coordinates of the rightmost point and the leftmost point:
DF = - 1 - (- 4)
DF = 3
DE = (- 1 - 1 / 3) - (- 4)
DE = 3 - 1 / 3
DE = 8 / 3
FG = 2 - (- 1)
FG = 3
FH = (3 + 1 / 2) - (- 1)
FH = 4 + 1 / 2
FH = 9 / 2
GH = (3 + 1 / 2) - 2
GH = 1 + 1 / 2
GH = 3 / 2
EH = (3 + 1 / 2) + (- 1 - 1 / 3)
EH = - 2 + (1 / 2 - 1 / 3)
EH = - 2 + 1 / 6
EH = - 11 / 6
To learn more on lengths: brainly.com/question/8552546
#SPJ1
Let's examine the given function first:
f(x) = x^2 + 1 is the same as f(x) = 1(x-0)^2 + 1.
The vertex of the graph of this function is at (0, 1).
Let x=0 to find the y-intercept: f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)
Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1. So: Graph y=x^2. Then translate the whole graph UP by 1 unit. That's it. Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.
It will be a reflex angle
A reflex angle is an angle that is more than 180° and less than 360°
Obtuse: More than 90° but Less than 180°
Acute: Less than 90°
