Line plots are used to represent data using lines and dots
The difference between the greatest amount of water and the least is 1/2
From the line plot (see attachment), we have the following parameters:


<h3>Calculating the difference</h3>
The difference (d) is then calculated as:

So, we have:

Subtract the common terms (8)

Take LCM


Reduce the fraction

Hence, the difference between the greatest amount of water and the least is 1/2
Read more about line plots at:
brainly.com/question/3521995
They both equal 78 degrees because they are the same angle which means that they have the same degrees for f and e.
Isnt it 15?? since theyre all suppose to be the samw
First simplify the square roots:

Then simplify the last two terms:

Since 61 is prime, you can't take a rational root out of it.