Check the picture below.
so hmmm let's find the distance AC, which is the only one missing for the perimeter.
![\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2 + b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{AC}\\ a=\stackrel{adjacent}{6}\\ b=\stackrel{opposite}{8}\\ \end{cases} \implies AC=\sqrt{6^2 + 8^2} \\\\\\ AC=\sqrt{100}\implies AC=10~\hfill \underset{Perimeter}{\stackrel{6~~ + ~~8~~ + ~~10}{\text{\LARGE 24}cm}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%20%2B%20b%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7BAC%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B6%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B8%7D%5C%5C%20%5Cend%7Bcases%7D%20%5Cimplies%20AC%3D%5Csqrt%7B6%5E2%20%2B%208%5E2%7D%20%5C%5C%5C%5C%5C%5C%20AC%3D%5Csqrt%7B100%7D%5Cimplies%20AC%3D10~%5Chfill%20%5Cunderset%7BPerimeter%7D%7B%5Cstackrel%7B6~~%20%2B%20~~8~~%20%2B%20~~10%7D%7B%5Ctext%7B%5CLARGE%2024%7Dcm%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ b=6\\ h=8 \end{cases}\implies A=\cfrac{1}{2}(6)(8)\implies A=\text{\LARGE 24}~cm^2](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20triangle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dbh%20%5Cbegin%7Bcases%7D%20b%3Dbase%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20b%3D6%5C%5C%20h%3D8%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%286%29%288%29%5Cimplies%20A%3D%5Ctext%7B%5CLARGE%2024%7D~cm%5E2)
13 5/9 - 8 1/6
= [ (13 * 9) + 5)/9 ] - [ (8*6)+1)/6 ]
= 122/9 - 49/6
= 122*6 - (49*9) / (9*6)
= ( 732 - 441 ) / 54
<span>= 5.389</span>
Answer:
If 10 is the average then 10 each side would be 20
so that 15 fits into 20 at 3/4
1- 3/4 = 1/4
So the answer is 1/4
Step-by-step explanation:
The first thing we are going to do is rewrite the expression correctly.
We have:
root (27x ^ 12 / 300x ^ 8)
Rewriting:
root ((27/300) * (x ^ 12 / x ^ 8))
root ((9/100) * (x ^ (12-8)))
root ((9/100) * (x ^ (4)))
root ((9/100) * (x ^ (4)))
3 * x ^ 2 * root ((1/100)
(3 * x ^ 2) / 10
(3/10) * (x ^ 2)
Answer:
(3/10) * (x ^ 2)
Answer:
Step-by-step explanation:
5y + 6y + 7y = 18y......any numbers that add(or subtract) to equal 18, stick them before the y....
or it could be : 10y + 10y - 2y = 18y or 5y + 10y + 3y or 30y - 20y + 8y....I could go on forever...lol
