We are to find how long will it take to return to the ground?
Answer:
t = 0.48 sec
Step-by-step explanation:
We are given;
initial velocity; vi = 40 ft/s
hi = 70 ft
acceleration due to gravity; a = 32 ft/s²
Now, we are given that the rocket's height as a function of time is;
h = -12at² + vit + hi
At ground, h = 0
Plugging in the relevant values to obtain ;
0 = -12(32)t² + 40t + 70
-384t² + 40t + 70 = 0
The roots of the equation gives; t = 0.48 sec
Answer:
*8
Step-by-step explanation:
6.75*8=54
Answer:
2 y^2 (3 y^2 + 7 y - 5)
Step-by-step explanation:
Factor the following:
6 y^4 + 14 y^3 - 10 y^2
Factor 2 y^2 out of 6 y^4 + 14 y^3 - 10 y^2:
Answer: 2 y^2 (3 y^2 + 7 y - 5)
Answer:
Step-by-step explanation:
Let the length is x, then the width is 1/4x.
<u>Find the perimeter of rectangle:</u>
- P = 2(l + w)
- P = 2(x + 1/4x) = 2x + 1/2x = 2 1/2x = 2.5x