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Vladimir [108]
3 years ago
13

You buy 21 lbs of cucumbers which are 92% water. A few days later they’re 85% water. How much do they weigh then?

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0
To solve this, you must find the initial weight of the cucumber. To do this, you must divide the weight by the percentage of water and multiply it by 100.

(21/92)×100=22.83lbs.

Then, you multiply it by 85% and divide it by 100. Or simply multiply it by 0.85.

22.83×0.85=19.41lbs.

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Please help me ASAP <br> Please help <br> No links please
lisov135 [29]

Answer:

a is height

b is length

c is width

Step-by-step explanation:

4 0
3 years ago
Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
Kai bought 120 shares of stock for $68.24 per share. He sold them nine months later for $85.89 per share. What was his capital g
nevsk [136]

Answer:

2118 dollars

Step-by-step explanation:

His capital gain is the difference in the (sell - buy) prices multiplied by the number of shares (120).

120 * (85.89 - 68.24) = 120 * 17.65 = 2118

The capital gain is a short term gain (held under a year)

The amount is 2118 dollars.

6 0
3 years ago
31
Viktor [21]

Answer:

no sure about the answer

6 0
2 years ago
in the voting for city council precinct 5,only 1/2 of all eligible voters cast votes. What fraction of all eligible voters voted
balandron [24]
Morgan, because 5/8 *2 = 10/16 and shell's is 6/20
3 0
3 years ago
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