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solong [7]
2 years ago
15

The work of a student to solve the equation 2(3x − 4) = 8 + 2x + 4 is shown below:

Mathematics
1 answer:
Lorico [155]2 years ago
8 0

Answer:

step 2; 6x-8=12+2x; she added instead of multiplying

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Alonzo, Alice, and Juan all solved the following problem but got different answers:
r-ruslan [8.4K]

Answer:

Juan believes the answer is -2/15.

Step-by-step explanation:

The given problem is :

\dfrac{-1}{3}\times \dfrac{2}{5}

We need to solve the problem.

\dfrac{-1}{3}\times \dfrac{2}{5}=\dfrac{-1\times 2}{3\times 5}\\\\=\dfrac{-2}{15}

So, the answer to the problem is \dfrac{-2}{15}. Hence, Juan is correct.

5 0
2 years ago
Complete the missing value in the solution to the equation. ​<br><br> y = 3x -7<br><br> (1, ?,)
Luda [366]

Answer: -4

Step-by-step explanation:

So, for y=3x-7, substitute the x with 1 (from (1,?) ) which gives you y=3(1)-7. Lastly, when you solve the equation, it would give you y=-4.

5 0
3 years ago
In the diagram below, ΔPQR ≅ ΔSTR. Complete the statement ∠PRQ ≅ ___ A. ∠SRT B. ∠RST C. ∠STR D. ∠T
Oduvanchick [21]

The complete statement is ∠PRQ ≅ <u>∠SRT</u>. The correction option is A. ∠SRT

<h3>Similar triangles </h3>

From the question, we are to complete the given statement

From the given information,

We have that ΔPQR ≅ ΔSTR

This means ΔPQR is congruent to ΔSTR

Then,

∠PQR ≅ ∠STR

∠PRQ ≅ ∠SRT

∠QPR ≅ ∠TSR  

Hence, the complete statement is ∠PRQ ≅ <u>∠SRT</u>. The correction option is A. ∠SRT

Learn more on Congruent Triangles here: brainly.com/question/28032367

#SPJ1

4 0
1 year ago
Plz answer both if you can
Harlamova29_29 [7]
I hope this helps you



130+x-5+x-35+x+30+75=360


3x=360-195


3x=165


x=55


m (B)=55-5=50
7 0
2 years ago
Branliest for who explains
Blababa [14]

Answer:

The cross section would be a square.

Step-by-step explanation:

The 2 ends of the rectangular prism are squares while the other 4 sides are rectangles. A cross section would be perpendicular to the rectangles, making the cross section a square. The cross section would be parallel to the end squares.

3 0
2 years ago
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