The work of a student to solve the equation 2(3x − 4) = 8 + 2x + 4 is shown below:

Mathematics

1 answer:

Lorico [155]3 years ago

8 0

Answer:

step 2; 6x-8=12+2x; she added instead of multiplying

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Write an equation in slope intercept form for a line that passes through the origin with a slope of 3/2

mrs_skeptik [129]

Answer: y = (3/2)x

m = 3/2 is the slope

(x1,y1) = (0,0) is the point we want the line to go through, aka the origin

Use point slope form, plug in the given values, and convert to slope intercept form

y - y1 = m(x - x1) .... point slope form

y - 0 = (3/2)*(x - 0) .... substitution

y = (3/2)x .... final answer in slope intercept form

4 0

3 years ago

Find the coordinates of point P

Drupady [299]

Here is the formula for finding a partitioning point:
x=x1+k(x2-x1), y=y1+k(y2-y1)
k is the ratio of the segment from the beginning point to the partitioning : the whole segment. In this case, k=AP:AB=5/16
so x=1+(5/16)*(-2-1)=1/16
y=6+(5/16)(-3-6)=51/16
so the answer is (-1/16, 51/16)

Please double check my calculation by yourself.

refer to this website for the formula and how to find k:

"This ratio is called k, and is determined by writing the numerator over the sum of the numerator and the denominator of the original ratio."
https://cobbk12.blackboard.com/bbcswebdav/institution/eHigh%20School/Courses/CCVA%20CCGPS%20Coordina....

6 0

3 years ago

Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t

juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

$\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}$