The work of a student to solve the equation 2(3x − 4) = 8 + 2x + 4 is shown below:

Mathematics

1 answer:

Lorico [155]2 years ago

8 0

Answer:

step 2; 6x-8=12+2x; she added instead of multiplying

You might be interested in

Why is it important to reduce radicals

OleMash [197]

Simplifying radical expressions expression is important before addition or subtraction because it you need to which like terms can be added or subtracted. If we hadn't simplified the radical expressions, we would not have come to this solution. In a way, this is similar to what would be done for polynomial expression.

7 0

2 years ago

What is 80%of 1,60 will mark brainliest

cluponka [151]

Answer:

Step-by-step explanation:

Converte 80% into a decimal (devide it by 100) = 0.8

Then multiply 0.8 by 1.60 = 1.28 (final result)

4 0

2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$