Question

What is the equation of a line that is perpendicular to -1 +3y=9 and passes through the point (-3, 2)?​

Answer 1

Answer:

y-2 = 3/10(x+3)

Step-by-step explanation:

3y = 10

y = 10/3

looking for perpendicular so slope = 3/10

using the given point

y-2 = 3/10(x+3)

Answer 2

Answer:

X=-3  

Step-by-step explanation:

Negative 1 plus 3y is equal to 9 so y is equal to negative 10/3 is a line parallel to the X-axis

So the line that's perpendicular to the X-axis and goes through the point negative 3,2 is x is equal to negative 3