What is the equation of a line that is perpendicular to -1 +3y=9 and passes through the point (-3, 2)?
2 answers:
Answer:
y-2 = 3/10(x+3)
Step-by-step explanation:
3y = 10
y = 10/3
looking for perpendicular so slope = 3/10
using the given point
y-2 = 3/10(x+3)
Answer:
X=-3
Step-by-step explanation:
Negative 1 plus 3y is equal to 9 so y is equal to negative 10/3 is a line parallel to the X-axis
So the line that's perpendicular to the X-axis and goes through the point negative 3,2 is x is equal to negative 3
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Answer:
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Step-by-step explanation:
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