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Kay [80]
2 years ago
15

What is the equation of a line that is perpendicular to -1 +3y=9 and passes through the point (-3, 2)?​

Mathematics
2 answers:
kati45 [8]2 years ago
6 0

Answer:

y-2 = 3/10(x+3)

Step-by-step explanation:

3y = 10

y = 10/3

looking for perpendicular so slope = 3/10

using the given point

y-2 = 3/10(x+3)

4vir4ik [10]2 years ago
5 0

Answer:

X=-3  

Step-by-step explanation:

Negative 1 plus 3y is equal to 9 so y is equal to negative 10/3 is a line parallel to the X-axis

So the line that's perpendicular to the X-axis and goes through the point negative 3,2 is x is equal to negative 3

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3 years ago
Use a table to multiply (–5a)(2a – 1). A) –15a B) 5a2 + 10a C) –10a2 – 5a D) –10a2 + 5a
Varvara68 [4.7K]

Answer:

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Open the bracket

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<em>hence the equivalent expression is -10a² + 5a</em>

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