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Arlecino [84]
2 years ago
14

How do you do these questions?

Mathematics
1 answer:
Doss [256]2 years ago
4 0

Step-by-step explanation:

(a) Fₙ₋₁ > 0, so Fₙ₊₁ > Fₙ.  Each term is bigger than the one before it, so the function is increasing, meaning the series will diverge to infinity.

(b) Fₙ₊₁ / Fₙ = (Fₙ + Fₙ₋₁) / Fₙ

Divide.

Fₙ₊₁ / Fₙ = 1 + (Fₙ₋₁ / Fₙ)

Rewrite the second fraction using negative exponent.

Fₙ₊₁ / Fₙ = 1 + (Fₙ / Fₙ₋₁)⁻¹

Take the limit of both sides as n approaches infinity.

lim(n→∞) Fₙ₊₁ / Fₙ = 1 + lim(n→∞) (Fₙ / Fₙ₋₁)⁻¹

Substitute with φ.

φ = 1 + φ⁻¹

Solve.

φ² = φ + 1

φ² − φ − 1 = 0

φ = [ -(-1) ± √((-1)² − 4(1)(-1)) ] / 2(1)

φ = (1 ± √5) / 2

Since the ratio can't be negative:

φ = (1 + √5) / 2

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The sum of the digits of a two-digit number is 11. When the digits are reversed, the new number is 45 more than the original num
Crank

Answer:

Step-by-step explanation:

Let the 10s digit = x

Let the units digit = y

x +y = 11                                   Sum of the digits = 11

10x + y + 45 = 10y + x             Reversed number is 45 more  than original #

10x - x + y + 45 = 10y              We subtracted x from both sides.

9x + y + 45 = 10y                    Subtract y from both sides.

9x + 45 = 10y - y                     Combine the right

9x + 45 = 9y

Put x +  y = 11 into the equation just found.

9x + 45 = 9(11 - x)                     divide through by 9

x + 45/9 = 11 - x                        add x to both sides

2x + 5 =     11                            Subtract 5 from both sides

2x = 11 - 5

2x = 6                                       Divide by 2

x = 6/2

x = 3

x + y = 11

3 + y = 11        

y = 11 - 3

y = 8

Now check it out.

the original number is 38

the new number is 83 which the digits are reversed.

83 - 38 = 45 just as it should.  

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(4^7/5^2)^ 3

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