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olga_2 [115]
3 years ago
11

A set of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. Find the value that is +3 standards dev

iation away from the mean
Mathematics
1 answer:
Sonbull [250]3 years ago
3 0
8.3 × 3 = 24.9

45 + 24.9 = 69.9

Hope this helps!
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Given b (x) = StartAbsoluteValue x + 4 EndAbsoluteValue, what is b (negative 10)?
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Answer:

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3 years ago
A metallurgist has an alloy with 10​% titanium and an alloy with 20​% titanium. He needs 100 grams of an alloy with 17​% titaniu
ser-zykov [4K]
\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentration\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{10\% alloy}&x&0.1&0.1x\\
\textit{20\% alloy}&y&0.2&0.2y\\
-----&-----&-------&-------\\
mixture&100&0.17&17
\end{array}

now, notice, we use the decimal format for the percent, namely 17% is 17/100 or 0.17 and so on

so....  we know, whatever "x" and "y" is, they must add up to 100 grams
thus    x + y = 100

and whatever the concentrated amount is, it must add up to 17 grams for the composition

thus   0.1x + 0.2y = 17

\bf \begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.1x+0.2y=17\\
----------\\
0.1x+0.2\left( \boxed{100-x} \right)=17
\end{cases}

solve for "x", to see how much is needed of the 10% alloy

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3 years ago
Change the function f(x) = –2x² + 12x – 6 into vertex form.
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Answer:

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<em>i hope </em><em>is </em><em>correct</em>

8 0
2 years ago
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