The possiblities that exist:
H, H, H
H, H, T
H, T, H <----
H, T, T
T, H, H
T, H, T
T, T, H
T, T, T
The answer is 1/8. Now the problem that you gave us isn't dependent upon anything, so more specifically the answer is 1/8 independent.
Nothing has actually happened therefore no odds have been decreased or increased.
Answer: 195
Step-by-step explanation:
Cost per student = $4
Total number who attended = n
The cost of the total of student who attended will be cost per student multiplied by the total number of students, that is
Total cos = 4n
Since, they are to pay $140 , for publicity, then the total cost becomes
T = 4n - 140
From the last statement
4n - 140 ≥ 640
4n ≥ 640 + 140
4n ≥780
n ≥ 780/4
n ≥ 195
That means at least 195 students must attend if the science club is to earn at least $ 640
Answer: ? = 72
Step-by-step explanation:
We will set up a proportion to solve.
Now, we will cross-multiply.
? * 35 = 56 * 45
35? = 2,520
? = 72
Answer:
Step-by-step explanation:
x-7y = -49
i) move x to the right-hand side and change its sign
-7y = -49-x
ii) change the signs on both sides of the equation
7y = 49+x
iii) divide both sides of the equation by 7
iv) use the commutative property to reorder the terms
* commutative property: a+b = b+a
Answer:
FRACTION DECIMAL
1/5( 1*2/5*2=2/10) 0.2
3/10 0.3
1/2(1*5/2*5=5/10) 0.5
7/10 0.7
3/4(3*25/4*25=75/100) 0.75
<u><em>NOTE</em></u>: To conert a fraction into decimal, it is required that the denominator be changed into 10, 100, 1000 and so on..... By changing the denominator, we have to first select the appropriate number by which you will be able to convert it into 10, 100 or 1000, and you are also required to multiply that number with the denominator as well as numerator. In the first question, 1/5 we can convert the denoinator into 10, 100 or 1000 as the denominator is 5, whatever you choose, the answer will be correct, so, 1*2/5*2 gives 2/10. Since 10 has one zero, the decimal point moves one time towards the left, which gives 0.2. And you can do the rest according to this way, considering the number of zeroes.
