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OverLord2011 [107]
3 years ago
12

Please help me!!!!!!!!!!!!!!!

Mathematics
1 answer:
ycow [4]3 years ago
7 0

Answer:

  7)  (f+g)(x) = 4^x +5x -5

  8)  (f-g)(x) = 4^x +x +5

Step-by-step explanation:

7) add the two expressions.

  (f+g)(x) = f(x) +g(x) = (4^x +3x) +(2x -5)

  (f+g)(x) = 4^x +5x -5

__

8) subtract g(x) from f(x).

  (f-g)(x) = f(x) -g(x) = (4^x +3x) -(2x -5) = 4^x +3x -2x +5

  (f-g)(x) = 4^x +x +5

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If the correlation between height and weight of a large group of people is 0.75​, find the coefficient of determination​ (as a​
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Independent variable is the predictor variable which is the height and dependent variable is the response variable which is weight in this scenario.

The square of correlation coefficient gives the coefficient of determination. It is denoted by R² (R squared).

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So,
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R² = 0.5625

R²  = 56.25 %
The coefficient of determination tells how much of the trend of dependent data can be explained by the independent data using the linear regression model. So in the given case, Height can explain 56.25% of the trend in the weight.
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ROOTS AND CUBES<br> Can someone please help me answer all 4 following?
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NOTES:

  • squared (²) means multiply that number by itself 2 times
  • cubed (³) means multiply that number by itself 3 times
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Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

=(7 - 2)\times \dfrac{1}{5}+9

=5 \times \dfrac{1}{5}+ 9

= 1 + 9

= 10

***************************************************************************************

8² = 8 · 8 = 64                                     11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

3 0
3 years ago
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