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3 years ago

I JUST NEED #13 please and thnx

Mathematics

1 answer:

emmainna [20.7K]3 years ago

3 0

$\bf \cfrac{18}{32}\implies \cfrac{2\cdot 3\cdot 3}{2\cdot 2\cdot 2\cdot 2\cdot 2}\implies \cfrac{3\cdot 3}{2\cdot 2\cdot 2\cdot 2}\implies \boxed{\cfrac{9}{16}}\qquad \checkmark \\\\[-0.35em] ~\dotfill\\\\ \cfrac{27}{48}\implies \cfrac{3\cdot 3\cdot 3}{2\cdot 2\cdot 2\cdot 2\cdot 3}\implies \cfrac{3\cdot 3}{2\cdot 2\cdot 2\cdot 2}\implies \boxed{\cfrac{9}{16}}\qquad \checkmark$

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Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?

Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

6 0

2 years ago

Rabies is an often-fatal disease typically transmitted through the bite of an infected animal. The state of Florida has been rec

slega [8]

Answer:

a) 3.6

b) 1.897

c)0.0273

d) 0.9727

Step-by-step explanation:

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The mean of a Poisson random variable X is μ.

mean=E(X)=μ=3.6.

The standard deviation of a Poisson random variable X is √μ.

standard deviation=S.D(X)=√μ=√3.6=1.897.

The probability for Poisson random variable X can be calculated as

P(X=x)=(e^-μ)(μ^x)/x!

where x=0,1,2,3,...

So,

P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!

P(no case of rabies)=P(X=0)=0.0273.

P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)

P(at least one case of rabies)=1-0.0273=0.9727

8 0

3 years ago

Find the GCF of 14a and 28ab

raketka [301]

The GCF would be 14a, because 14a x 1 = 14a, and 14a x 2b = 28ab.

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2 years ago

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Answer:

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