What are all the values of x that make the quadratic A equation below true? x²

Find the value of..

Zina [86]

Step-by-step explanation:

[1/2]^-2= 4

[1/3]^-2=9

[1/4]^-2=16

So sum is 4+9+16=29

Hope this helps you.

6 0

3 years ago

What is the range of the function f(x)= 2 + 4 when the domain is {-2, 0, 3}?

Orlov [11]

The domain is the possible input values "x" .. in this case [-4, -2, 0, 2, 4]

The range are the possible output values of f(x)

We need to solve f(x) = 3.2x for each value in our domain

f(-4) = 3.2(-4) = -12.8

f(-2) = 3.2(-2) = -6.4

f(0) = 3.2(0) = 0

f(2) = 3.2(2) = 6.4

f(4) = 3.2(4) = 12.8

4 0

3 years ago

Help me understand this!!!!!!!!!! m

gregori [183]

Answer:

Your question does not make sense

Step-by-step explanation:

Pls give me points for my answer anyways.

We're no strangers to love

You know the rules and so do I

A full commitment's what I'm thinking of

You wouldn't get this from any other guy

I just wanna tell you how I'm feeling

Gotta make you understand

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

We've known each other for so long

Your heart's been aching but you're too shy to say it

Inside we both know what's been going on

We know the game and we're gonna play it

And if you ask me how I'm feeling

Don't tell me you're too blind to see

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

Never gonna give, never gonna give

(Give you up)

(Ooh) Never gonna give, never gonna give

(Give you up)

We've known each other for so long

Your heart's been aching but you're too shy to say it

Inside we both know what's been going on

We know the game and we're gonna play it

I just wanna tell you how I'm feeling

Gotta make you understand

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

7 0

3 years ago

If StartFraction pi Over 2 EndFraction less than t less than pi , which of the following is true?

oksian1 [2.3K]

Answer:

b. cosine t less than 0 and cotangent t greater than 0

Step-by-step explanation:

We have the following relation

$\frac{\pi }{2} < t$

if we apply the cosine function in the relation we get:

$cos\frac{\pi }{2}$

$-1$

the cosine of t is between 0 and -1 then (cosine t less than 0)

If we now apply cotangent function in the relation:

$cotan\frac{\pi }{2}$

$0$

This means that cotang is greater than 0, therefore the correct answer is b. cosine t less than 0 and cotangent t greater than 0

5 0

3 years ago

Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i

dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

$v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s$

Also,

$v=r\omega$

Where

$\omega$ is the angular speed

So,

$\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s$

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

8 0

4 years ago

What are all the values of x that make the quadratic A equation below true? x² – 16=0