Y = 5x + 5
y - x = 5
You can use substitution to solve this system. Use y's expression (5x + 5) for y in the second equation to solve for x:
y - x = 5
5x + 5 + x = 5
6x + 5 = 5
6x = 0
x = 0
Substitute your value for x into one of the original equations to y:
y = 5x + 5
y = 5(0) + 5
y = 5
Finally, substitute both values into both original equations to check your work:
5 = 5(0) + 5 --> 5 = 5 <--True
5 - 0 = 5 --> 5 = 5 <--True
Answer:
x = 0
y = 5
Answer:
`1/2
Step-by-step explanation:
can i have brainliest
Easy, just write out the multiple of the numbers.
4: 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60
7: 7,14,21,28,35,42,49,56,63,70
Etc.
But a few common multiples:
28,56,84,112,140
These are the first 5 common multiples of 4 and 7.
Answer:
-21/22
Step-by-step explanation:
1.Apply fraction cross multiply
2. Simplify
3.Expand
4.Subtract 24 from both sides
5.simplify
6. Subtract 18x form both sides
7.Simpiify, then divide both sides by -22to get answer.
