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3 years ago

Y=3x+2;x=0.5 what is the answer

Mathematics

2 answers:

Ulleksa [173]3 years ago

8 0

Answer:

y=3.5

Step-by-step explanation:

Elena-2011 [213]3 years ago

4 0

Answer:

x =(1-√61)/6=-1.135

x =(1+√61)/6= 1.468

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(3x2 - x) - 5 = 0

Step 2 :

Trying to factor by splitting the middle term

2.1 Factoring 3x2-x-5

The first term is, 3x2 its coefficient is 3 .

The middle term is, -x its coefficient is -1 .

The last term, "the constant", is -5

Step-1 : Multiply the coefficient of the first term by the constant 3 • -5 = -15

Step-2 : Find two factors of -15 whose sum equals the coefficient of the middle term, which is -1 .

-15

-14

-5

-2

-3

-1

14Two solutions were found :

x =(1-√61)/6=-1.135

x =(1+√61)/6= 1.468

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(3x2 - x) - 5 = 0

Step 2 :

Trying to factor by splitting the middle term

2.1 Factoring 3x2-x-5

The first term is, 3x2 its coefficient is 3 .

The middle term is, -x its coefficient is -1 .

The last term, "the constant", is -5

Step-1 : Multiply the coefficient of the first term by the constant 3 • -5 = -15

Step-2 : Find two factors of -15 whose sum equals the coefficient of the middle term, which is -1 .

-15

-14

-5

-2

-3

-1

Step-by-step explanation:

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Hello from MrBillDoesMath!

Answer:

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Triangle PQR has vertices P(4,-1),Q(-2,7), and R(9,9). Find an equation of the median and altitude from R.

Reil [10]

If we are drawing altitude from R the PQ will be base of this triangle. So we can say Median from R will cut on Midpoint of PQ. So firstly we will find mid point of PQ Which is S given as below:
P(4,-1) , Q (-2,7)

Let Co-ordinate of S is (x,y)
So $x = \frac{x_1+x_2}{2}$
$x = \frac{4-2}{2} = \frac{2}{2} = 1$

$y = \frac{y_1+y_2}{2}$
$y = \frac{-1+7}{2} = \frac{6}{2}= 3$
So midpoint of PQ is S(1,3).

Now we can find equation of RS
Co-ordinate of R is (9,9) and and S is (1,3).

In general equation of line from two point $(x_1 , y_1)$ and $(x_2,y_2)$ is
$(y-y_1) = \frac{y_2-y_1}{x__2-x_1}(x-x_1)$

So equation of RS is

$(y-9) = \frac{9-3}{9-1} (x-1)$
$(y-9) = \frac{6}{8}(x-1)$
$8(y-9) = 6(x-1)$
$8y-72 = 6x - 6$
$-72+6 = 6x - 8y$
$-66 = 6x-8y$

So the equation of median is 6x - 8y = -66

5 0

3 years ago

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