Answer:
Quadrant 1 is the top right side. Quadrant 2 is top left. Quuadrant 3 is bottom left. Quadrant 4 is bottom right.
Step-by-step explanation:
<h3>
You must mark the number on the quadrants starting by the middle is the axis (0). Then you count from 1 to how ever much the quadrants end. There the y axis and the x. Those are the lines that seperate the 4 quadrants. Quadrant 1 is both postive #. quadrant 2 is a negative number and a postive. depending on how the x and y are. the X axis is spostive the y is negative. Point A is (10,4) and its quadrant is 4. You must count all the boxes which go all the way up to 10. You must start in the center then either go up for Y or down. Go right or left for X. B is -8,9</h3><h3>
</h3><h3>
I hope this helped. It took me a long time. </h3>
For this case we have that by definition, the equation of the line of the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have two points through which the line passes:
We found the slope:
Substituting we have:
Thus, the equation is of the form:
We substitute one of the points and find the cut-off point:
Finally, the equation is:
ANswer:
what do you need help with?
Answer:
$6
Step-by-step explanation:
This is for one pencil to each student. Since each box is $3, and she has 25 students, you would figure out how many students are left out with one box, and since you only have one left, you only need one more box. That would mean two boxes, so $3x2= $6
Answer:
3
Step-by-step explanation:
5x-22 = -7
5x=15
x = 3
