Answer:
Sabemos que:

y tenemos que:

Con esto podemos encontrar el valor de a:
8*a/(a+ 4) = 6
8*a = 6*(a + 4) = 6*a + 24
8a - 6a = 24
2a = 24
a = 24/2 = 12.
Tambien sabemos que:

Y de ahí podemos despejar b:
(16*b)/(b + 8) = 12
16*b = 12*(b + 8) = 12b + 96
16b - 12b = 96
4b = 96
b = 96/4 = 24
Entonces tenemos a = 12 y b = 24, y el MH de a y b es:
MH(12,24) = 2*12*24/(12 + 24) = 24*24/36 = 16
Answer:
zeros: x = 5, or (5, 0)
domain: x ≥ -4
Step-by-step explanation:
The zeros are the values of x where the graph crosses the x-axis. The graph crosses at x=5, so that is the zero.
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The domain is the set of x-values for which the function is defined. There is no graph for x < -4, so the graph is only defined for x ≥ -4. The domain is x ≥ -4.
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The graph has the appearance of the graph of ...

To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
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The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
Answer:
565647393
Step-by-step explanation:
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Just returning the favor.
Answer:
23
Step-by-step explanation:
According to the diagram, two sum of <1 and <2 is 180 degrees
Hence 3x+30+81 = 180
3x+111 = 180
3x =180-111
3x = 69
x = 69/3
x = 23