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3 years ago

Help fast please k it dued today

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

8 0

Answer:

1. -72

2. -66

Step-by-step explanation:

Hope this helps you :)

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Elaine bought 3 4/5 pounds of apples for $1.99 per pound, 3/4 pound of pears for $2.25 per pound, and 3 2/3 pounds bananas for $

stiv31 [10]

Answer:

1.$6.41

2.$1.68

3.$7.56

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the missing step in this proof

bagirrra123 [75]

Ok the parralelogram is 25 units and I think the angle of BCD would be 53. I got this by subtracting 127 from 180 since that should give you the whole square. and I got teh units by adding the lines BC and AB... Hope this helped

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2 years ago

A citrus grower ships grapefruit in boxes of 10. One season, The growers shipped 20,400 boxes of grapefruit. How many grapefuit

erica [24]

204,000 grapefruit.

There are 10 grapefruit in each box and there are 20,400 boxes; you need to multiply the number of grapefruits in each box (10) times the number of boxes (20,400)

10x20,400=204,000

Don't forget the units! In this problem, the units are grapefruit.

3 0

3 years ago

How many words of five letters can be created that start with the letter T, contain 2 other consonats and end with 2 vowels? Not

Jet001 [13]

If we're only counting 5 vowels (A, E, I, O, U) and 20 consonants (everything else, minus T), then there are

$\dbinom52=\dfrac{5!}{2!(5-2)!}=10$

ways of picking the vowels, and

$\dbinom{20}2=\dfrac{20!}{2!(20-2)!}=190$

ways of picking the consonants.

We want the word to start with T, and we'll allow any arrangement of the other 4 letters, so that the total number of words is

$4!\dbinom52\dbinom{20}2=\boxed{45,600}$

Keep in mind that this means words like TRIES and TIRES are treated as different.

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3 years ago

Distance between parallel lines y=3x+10 and y=3x-20

Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).

2. Use formula $d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}$ to find the distance from point $(x_0,y_0)$ to the line Ax+By+C=0.

The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

$d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}$ .

3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.

Answer: $d=3\sqrt{10}$ .

4 0

2 years ago