So you start with a 88.1%.
Here is how I figure it...
If you get a 15 out of 15 on an assignment, that would be a 100% for your assignment grade.
You take 100% and add it to your 88.1% and you get 188.1%. That doesn't seem reasonable for a grade though does it...
So you take that 188.1% and you divide it by 2 (divide it in half) and you get 94.05%.
So if you get 15 out of 15 on your assignment your grade will go up to a 94.05% as I figure.
Word problem:
15 out of 15= 100%+88.1%= 188.1%÷2= 94.05%
Your final grade as I figure would be a <em><u>94.05%</u></em>
Answer:
-$1,500 more expensive
Explanation:
Calculation for How much cheaper or more expensive would it be to use the stainless-steel pump rather than a new brass pump
Using this formula
Cheaper or more expensive=Brass pump value-( Current pump value+Pump reconfigure extra amount spent)
Let plug in the formula
Cheaper or more expensive =$6,000-($7,000+$500)
Cheaper or more expensive =$6,000-$7,500
Cheaper or more expensive =-$1,500 more expensive
Therefore based on the information given the stainless steel pump will be $ 1500 more expensive than the brass pump.
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brainly.com/question/20815848
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Answer:
The correct answer is: Build-up approach
.
Explanation:
The Build-up approach estimates the sales potential of the company by calculating how much of a product could be purchased in a given period by a potential buyer in a specific geographic region. The calculation is then multiplied by the number of potential customers, adding the sum of all the considered geographic areas.
Answer:
the expected return from the investment is higher than that of those investments whose standard deviation is greater than zero.
Explanation:
As for the coefficient of variation which clearly defines the difference in values from the mean value in the data set.
It clearly defines as standard deviation/mean.
Where standard deviation is 0 the coefficient will also be 0 which shall represent the risk associated with it.
The least the coefficient of variation the least the risk with maximum return.
Thus, the correct statement will be concluding that the expected return from this investment will be higher than the returns from the project in which standard deviation is more than 0.