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e-lub [12.9K]
3 years ago
15

A box Jelly fish travels at a rate of 6.5 feet per second. What is the distance after 5 seconds?

Mathematics
2 answers:
Ronch [10]3 years ago
8 0

Answer:

32.5 feet per 5 seconds

Step-by-step explanation:

multiply 5 by 6.5 you get 32.5

Darina [25.2K]3 years ago
4 0

Answer:

32.5ft

Step-by-step explanation:

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If and , find .<br><br> A. <br> B. <br> C. <br> D.
trapecia [35]
Answer: option D. 2x^2 + (3/2)x  - 5

Explanation:

1) polynomials given:

 f(x) = x/2 - 2 and g(x) = 2x^2 + x - 3

2) question: find (f + g) (x)

That means that f(x) + g(x), so you have to add up the two polynomials given.

3) x/2  - 2 + 2x^2 + x - 3

4) Combine like terms:

a) terms with x^2: you only have 2x^2, so it is not combined with other term.

b) terms with x: x/2 + x

that is a sum of fractions: x/2 + x = [x + 2x] / 2 = 3x / 2 = (3/2)x

c) constant terms: - 2 + (-3) = - 2 - 3 = - 5

5) Result: 2x^2 + (3/2)x - 5

That is the option d.


4 0
3 years ago
Gabby makes banana bread at her bakery every Monday and Wednesday,
garri49 [273]

Answer:

Monday:

<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><em>3</em>

<em>Tablespoon</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><u><em>3</em><em>0</em></u>

<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><u><em>7</em><em>5</em></u>

Wednesday

<em>Cups</em><em> </em><em>of</em><em> </em><em>Sugar</em><em>:</em><em> </em><u><em>1</em><em>.</em><em>1</em><em>2</em></u>

<em>Tablespoons</em><em> </em><em>of</em><em> </em><em>Butter</em><em>:</em><em> </em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em>

<em>No</em><em>.</em><em> </em><em>of</em><em> </em><em>Bananas</em><em>:</em><em> </em><em>2</em><em>8</em>

5 0
3 years ago
El equivalente de 4/6 ​
Diano4ka-milaya [45]
La respuesta es 2/3!
6 0
2 years ago
A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a de
marin [14]

Answer:

\frac{23}{4} feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 \frac{1}{2} feet

                                                                             =   \frac{5}{2} feet

The depth of the fish to its initial position at 4:00 pm = 3 \frac{1}{4} feet

                                                                              = \frac{13}{4} feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

                                        =  \frac{5}{2} + \frac{13}{4}

                                        = \frac{10 + 13}{4}

                                         = \frac{23}{4}

The position of the fish with respect to the water's surface at 4:00 pm is \frac{23}{4} feet.

8 0
3 years ago
Given<br> f(x) = -4(x+5),<br> what is the value of<br> f(-3)?<br> 
sp2606 [1]

Answer:

f(-3)=-8

Step-by-step explanation:

plug -3 in as x

-4(-3+5)

12-20

-8

4 0
3 years ago
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