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3 years ago

PLEASE HELP ASAP 20 POINTS!!!!!!

Mathematics

2 answers:

Jet001 [13]3 years ago

6 0

1 A. 2A. 3 D. 4 C. 5 B

tankabanditka [31]3 years ago

4 0

Number 1.
Subtracting Negative Is The Same As Adding.
So, It Would Be Equivalent To A
Number 2:
Subtracting From A Negative Is Making The Negative Number Larger.
So, It Would Be A
Number 3:
Positive Plus Positive Makes Larger Positive:
37 + 13 = 50.
So, 3 Is D.
Number 4:
Adding Negative Is Making Positive Numbers Smaller.
So, It Is C.
Number 5:
This Is C, Because -30 + 30 = 0 + 1 = 1

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63x^12-35x^6 help pls

zmey [24]

Answer:

7x^6×(9×^6-5)

Step-by-step explanation:

63x^12-35x^6

7x^6×(9×^6-5)

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2 years ago

The amount of time it takes an ice cube to melt varies inversely to the air temperature. At 30 degrees Celsius, the ice will mel

Anon25 [30]

Answer:

hope this helps A block of ice melts in 2.5 hours when the temperature is 54 degrees.

Step-by-step explanation:therefore you can increase 2.5 and decrease 54 to whatever number you need

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2 years ago

Iv) 6x+3y=6xy 2x + 4y= 5xy

Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5 - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

$y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}$

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0

2 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

A(1) = -11 a(n) = a(n − 1). 10 What is the 4th term in the sequence?

neonofarm [45]

Answer:

a(n)= a(n-1) .10

Clearly see the equation

you can do it directly Apply logic

Every n th term is 10 times of previous n-1 th term

That is common ratio an/a(n-1)= 10

So, We have to find 4 th term

So, 4 th term is simply

1st term × (common ratio)^(4-1)

-11( 10)^3

-11000

Thanks

3 0

3 years ago