The Answers are B and C
Its B because 12 is MORE than twice as much as M. Meaning 140 is larger than 2*m
Its C because again it is MORE than twice as much as M. Meaning that 140 is larger than 2m.
Answers;B,C
Hope this helped!
Answer:
![(5\pi-11.6)\ ft^{2}](https://tex.z-dn.net/?f=%285%5Cpi-11.6%29%5C%20ft%5E%7B2%7D)
Step-by-step explanation:
we know that
The area of the shaded region is equal to the area of the sector minus the area of the triangle
step 1
Find the area of the circle
the area of the circle is equal to
![A=\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D)
we have
![r=5\ ft](https://tex.z-dn.net/?f=r%3D5%5C%20ft)
substitute
![A=\pi (5)^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20%285%29%5E%7B2%7D)
![A=25\pi\ ft^{2}](https://tex.z-dn.net/?f=A%3D25%5Cpi%5C%20ft%5E%7B2%7D)
step 2
Find the area of the sector
we know that
The area of the circle subtends a central angle of 360 degrees
so
by proportion find out the area of a sector by a central angle of 72 degrees
![\frac{25\pi}{360}=\frac{x}{72}\\ \\x=72*25\pi /360\\ \\x=5\pi\ ft^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B25%5Cpi%7D%7B360%7D%3D%5Cfrac%7Bx%7D%7B72%7D%5C%5C%20%5C%5Cx%3D72%2A25%5Cpi%20%2F360%5C%5C%20%5C%5Cx%3D5%5Cpi%5C%20ft%5E%7B2%7D)
step 3
Find the area of triangle
The area of the triangle is equal to
![A=\frac{1}{2}(2.9+2.9)(4)= 11.6\ ft^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%282.9%2B2.9%29%284%29%3D%2011.6%5C%20ft%5E%7B2%7D)
step 4
Find the area of the shaded region
Subtract the area of the triangle from the area of the sector
![(5\pi-11.6)\ ft^{2}](https://tex.z-dn.net/?f=%285%5Cpi-11.6%29%5C%20ft%5E%7B2%7D)
Answer:
4x+11 is the answer.
Step-by-step explanation:
( 4*2-x+3)-(3*2-5x-6)
=(8-x+3)-(6-5x-6)
=(11-x)-(0-5x)
=(11-x)-(-5x)
=11-x+5x
=11+4x
= 4x+11
Answer:
119.4
Step-by-step explanation:
Big Brain Dude <:
Jimmy asked me for 8 of my 17 cookies so i gave them to him which left me with nine so I went to the store and got 5 which gives me 14
I really dont get what your asking but I hope this helps you. If it doesn't please ask me for help ;)