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11111nata11111 [884]
1 year ago
6

Find a formula for the nth term in this arithmetic sequence first term -2 common difference an=

Mathematics
1 answer:
malfutka [58]1 year ago
3 0
The formula for the problem is: An = 8(n-1) - 2

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A shoe company sends out 7 trucks loaded with nursing shoes that cost the company $ 1,572per truck if they send out 750 boxes pe
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1572*7=11004

750*125.40=94050

94050-11004=83046

the profit is $83046

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3 years ago
Write 26 weeks in years​
WARRIOR [948]

Answer:

.5 years

Step-by-step explanation:

52 weeks = 1 year

26 weeks * 1 year/52 weeks = .5 years

7 0
3 years ago
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a car travels 54.9 miles in an hour. if the car continues at the same speed for 12hours,how many miles will it travel
Ilia_Sergeevich [38]
Here's what you have to do: multiply. 54.9×12= 658.8. So, he traveled 658.8 miles in twelve hours.
7 0
3 years ago
Write first three common multiple of 3 , 5 and 6​
ratelena [41]

Answer:

LCM of 3, 5, and 6 is the smallest number among all common multiples of 3, 5, and 6. The first few multiples of 3, 5, and 6 are (3, 6, 9, 12, 15 . . .), (5, 10, 15, 20, 25 . . .), and (6, 12, 18, 24, 30 . . .) respectively. There are 3 commonly used methods to find LCM of 3, 5, 6 - by division method, by prime factorization, and by listing multiples.

Step-by-step explanation:

6 0
2 years ago
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The number of events is 29​, the number of trials is 298​, the claimed population proportion is​ 0.10, and the significance leve
Nina [5.8K]

Answer:

z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155  

p_v =2*P(Z  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

Step-by-step explanation:

1) Data given and notation

n=298 represent the random sample taken

X=29 represent the events claimed

\hat p=\frac{29}{298}=0.0973 estimated proportion

p_o=0.1 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.1 or no.:  

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

We can do the test also in R with the following code:

> prop.test(29,298,p=0.1,alternative = c("two.sided"),conf.level = 1-0.05,correct = FALSE)

7 0
2 years ago
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