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sleet_krkn [62]
3 years ago
6

A new extended-life light bulb has an average life of 750 hours, with a standard deviation of 50 hours. If the life of these lig

ht bulbs approximates a normal distribution, about what percent of the distribution will be between 600 hours and 900 hours?
Mathematics
1 answer:
Yuki888 [10]3 years ago
8 0

Answer:

99.7% of the distribution will be between 600 hours and 900 hours.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 750

Standard deviation = 50

What percent of the distribution will be between 600 hours and 900 hours?

600 = 750 - 3*50

600 is 3 standard deviations below the mean

900 = 750 + 3*50

900 is 3 standard deviations above the mean

By the Empirical Rule, 99.7% of the distribution will be between 600 hours and 900 hours.

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△STR≅△LMN, SR=7b+8, and LN=11b−12. Find b and SR.
mote1985 [20]

Answer:

<em>b = 5</em>

Step-by-step explanation:

7 0
3 years ago
Can anybody helppp meee please
crimeas [40]

Answer:

r^2=(A/pi)

Step-by-step explanation:

if A=pi*r^2 then maybe dividing by pi to get r^2 alone says r^2=(A/pi) or to get rid of the exponent you may square root each side so r=(sqrt(A/pi))

3 0
3 years ago
A variable is normally distributed with mean 6 and standard 2 deviation .
Tju [1.3M]

The normal distribution is also known as the Gaussian distribution. The percentage of all possible values of the variable that are less than 4 is 15.87%.

<h3>What is a normal distribution?</h3>

The normal distribution, also known as the Gaussian distribution, is a symmetric probability distribution about the mean, indicating that data near the mean occur more frequently than data distant from the mean. The normal distribution will show as a bell curve on a graph.

A.) The percentage of all possible values of the variable that lie between 5 and 9.

P(5<X<9) = P(X<9) - P(5<X)

               = P(z<1.5) - P(-0.5<z)

               = 0.9332 - 0.3085

               = 0.6247

               = 62.47%

B.) The percentage of all possible values of the variable that exceed 1.

P(X>1) = 1 - P(X<-2.5)

          = 1-0.0062

          = 0.9938

          = 99.38%

C.) The percentage of all possible values of the variable that are less than 4.

P(X<4) = P(X <4)

           = P(z<-1)
           = 0.1587

           = 15.87%

Learn more about Normal Distribution:

brainly.com/question/15103234

#SPJ1

8 0
2 years ago
I have 54 oranges. I give 28 away and saved 5 for my family. How many oranges do I have?
ratelena [41]

Answer:

Either <u><em>26 or 21</em></u>  depending on if you count the saved oranges or not.

Step-by-step explanation:

54 - 28 = 26

54 - 28 - 5 = 21

6 0
3 years ago
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Cerrena [4.2K]
Y=$175+x I think this is it? one half of 175 is 87.5 so you know.
8 0
3 years ago
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