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Firdavs [7]
4 years ago
11

Consider the expression ab2 and a2b2. Are the two expressions equivalent? Which properties did you use to prove or disprove the

equivalency?
Mathematics
1 answer:
bearhunter [10]4 years ago
4 0

Let

x=ab^{2} \\ y=a^{2}b^{2}

we know that

if x and y are equivalent

then

\frac{x}{y} =1

so

<u>Divide the value of x by y</u>

\frac{x}{y} = \frac{ab^{2}}{a^{2}b^{2}}= \frac{1}{a} \\\\ \frac{1}{a} \neq 1

<u>therefore</u>

The expressions are not equivalent

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Simora [160]

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8 0
3 years ago
The sum of three times a number and 4 is between -8 and 10
Alex
Alright, so we can start by writing it out by their signs.
Using PEMDAS (Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction) and noting that the inequality comes last, we can write it as the sum of (addition), then three times (multiplication) a number and 4 (ties in with the sum of, making it also addition).Note that we know that "a number and 4" means addition because it doesn't state to do anything with it, and we don't know what "the sum of" referred to with numbers, so they match up. Therefore, we have multiplication (3 times a number=3 * number), then addition (3 times a number, or 3 * number, added to 4, or 3*number+4), and we can do the inequality. Between -8 and 10 means that it is greater than -8 and less than 10, as 10 is the larger number, writing it out as -8< (less than) 3*number+4 < (3*number+4 is less than 10, so we have another less than sign) 10. Subtracting 4 from everything using the subtraction property of equality, we get -12<3*number<6. Next, we can divide everything by 3 to separate the number and get -4<number<2.

Feel free to ask further questions!
5 0
4 years ago
HELPP If f(x)=x^(2)+3x-2, find f(-2)
Vikki [24]

Answer:

f(-2)=-12

Step-by-step explanation:

just plug in -2 for x values

and solvee

f(-2)=-2^2+3(-2)-2

should be -12

f(-2)=-12

6 0
3 years ago
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agasfer [191]
8/25

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(if it says to simplify: -9/23)
7 0
3 years ago
I had problem in these questions. Can anyone help me please?
Lyrx [107]
Use google that my advice 
5 0
3 years ago
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