Answer:
Step-by-step explanation:
Given
Cost of Textbooks ---- Frequency
$25 up to $35 ----- 2
$35 up to $45 ------- 5
$45 up to $55 ------- 7
$55 up to $65 ------ 20
$65 up to $75 ---- -- 16
Required
Determine the relative class frequency for the $25 up to $35 class
First, we need to get the total frequency
Next, is to write out the frequency of $25 up to $35 class
Divide this frequency by the total frequency; This gives the relative frequency
Hence;
Option D answers the question
Answer:
10x2 + 2x + 13.
Step-by-step explanation:
10x2 + 3 - (-2x - 10) (Note you have to put the -2x - 10 in brackets).
= 10x2 + 3 + 2x + 10 (Distributing the negative over the brackets).
= 10x2 + 2x + 13.
Yes, I will list acute first (<90) and obtuse second (>90) and they need to add to 180
10 and 170
20 and 160
30 and 150
40 and 140
50 and 130
60 and 120
70 and 110
80 and 100 and so on
Answer:
i think c
Step-by-step explanation:
Kilobyte = 2^10 bytes
gigabyte = 2^30 bytes
terabyte is the product of a kilobyte and a gigabyte....so we multiply
2^10 * 2^30 = 2^(10 + 30) = 2^40 <== a terabyte
** exponent rule : a^b * a^c = a^(b + c)
