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Novosadov [1.4K]
3 years ago
7

Fill in the term to complete each sentence. A wave carries from one place to another. Mechanical waves carry energy through .

Physics
2 answers:
Tamiku [17]3 years ago
6 0

Answer:

energy and matter

Explanation:

 

Franky Mason
2 years ago
you are right thank you
brilliants [131]3 years ago
5 0

Answer:

disturbance and energy

Franky Mason
2 years ago
you are wrong
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I need the definitions to
vlabodo [156]
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5 0
3 years ago
Read 2 more answers
A spring whose stiffness is 1140 n/m has a relaxed length of 0.51 m. if the length of the spring changes from 0.26 m to 0.79 m,
Ugo [173]
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
Read more on Brainly.com - brainly.com/question/1581851#readmore
7 0
4 years ago
An electron is trapped between two large parallel charged plates of a capacitive system. The plates are separated by a distance
Lorico [155]

Answer:

The electron will get at about 0.388 cm (about 4 mm) from the negative plate before stopping.

Explanation:

Recall that the Electric field is constant inside the parallel plates, and therefore the acceleration the electron feels is constant everywhere inside the parallel plates, so we can examine its motion using kinematics of a constantly accelerated particle. This constant acceleration is (based on Newton's 2nd Law:

F=m\,a\\q\,E=m\,a\\a=\frac{q\,E}{m}

and since the electric field E in between parallel plates separated a distance d and under a potential difference \Delta V, is given by:

E=\frac{\Delta\,V}{d}

then :

a=\frac{q\,\Delta V}{m\,d}

We want to find when the particle reaches velocity zero via kinematics:

v=v_0-a\,t\\0=v_0-a\,t\\t=v_0/a

We replace this time (t) in the kinematic equation for the particle displacement:

\Delta y=v_0\,(t)-\frac{1}{2} a\,t^2\\\Delta y=v_0\,(\frac{v_0}{a} )-\frac{a}{2} (\frac{v_0}{a} )^2\\\Delta y=\frac{1}{2} \frac{v_0^2}{a}

Replacing the values with the information given, converting the distance d into meters (0.01 m), using \Delta V=100\,V, and the electron's kinetic energy:

\frac{1}{2} \,m\,v_0^2= (11.2)\,\, 1.6\,\,10^{-19}\,\,J

we get:

\Delta\,y= \frac{1}{2} v_0^2\,\frac{m (0.01)}{q\,(100)} =11.2 (1.6\,\,10^{-19})\,\frac{0.01}{(1.6\,\,10^{-19})\,(100)}=\frac{11.2}{10000}  \,meters=0.00112\,\,metersTherefore, since the electron was initially at 0.5 cm (0.005 m) from the negative plate, the closest it gets to this plate is:

0.005 - 0.00112 m = 0.00388 m [or 0.388 cm]

8 0
4 years ago
Floating in deep space, you find yourself at rest next to a small asteroid. You reach out and tap the asteroid with a hammer. Wh
Andrei [34K]

Answer:

There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

Explanation:

For this exercise we will propose its solution from Newton's third law, which states that every action has a reaction of equal magnitude, but felt different.

As it is in space, we must assume that it is not subject to the gravitational attraction of nearby bodies, except the asteroid that attracts it. When he extends his hand and hits the asteroid, he exerts a force on him, by Newton's third law he responds with a force of equal magnitude applied to the astronaut, therefore without the two they are not united they could separate if this force is greater than the force of universal attraction between the two.

In summary There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

4 0
3 years ago
An object is falling from a height of 7.5 meters. At what height will its velocity be 7 meters/second?
Ivanshal [37]

Answer:

5.0 m

Explanation:

The velocity of the object at time t is given by

v=at

where a=9.8 m/s^2 is the acceleration of gravity and t is the time. If we substitute v=7 m/s, we can find the time t at which the velocity became 7 m/s:

t=\frac{v}{a}=\frac{7 m/s}{9.8 m/s^2}=0.71 s

The height of the object at time t, h(t), is given by the equation

h(t)=h_0 -\frac{1}{2}at^2

where h_0 = 7.5 m is the initial height. By substituting t=0.71 s inside the equation, we find the height h(t) at which the velocity is 7 m/s:

h(0.71 s)=7.5 m- \frac{1}{2}(9.8 m/s^2)(0.71 s)^2=5.0 m

8 0
3 years ago
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